GMATPrepNow wrote:
If \(x\) is a negative integer, what is the value of \(x\)?
(1) \(x^2 + 40x + 398 < 0\)
(2) \((x+17)(x+20) < 0\)
Given: x is a negative integer Target question: What is the value of x? Statement 1: \(x^2 + 40x + 398 < 0\) If we recognize that x² + 40x + 398 is very close to the PERFECT SQUARE x² + 40x + 400, we can quickly deal with statement 1
Take: x² + 40x + 398 < 0
Add 2 to both sides to get: x² + 40x + 400 < 2
Factor: (x + 20)(x + 20) < 2
In other words: (x + 20)² < 2
Since we're told x is an INTEGER, we can see that there are 3 values of x that satisfy the inequality (x + 20)² < 2
So,
x can equal -21, -20 or -19 Statement 2: \((x+17)(x+20) < 0\) Notice that, when -20 < x < -17, we see that (x+17)(x+20) = (NEGATIVE)(POSITIVE) = NEGATIVE
In other words, when x is BETWEEN -20 and -17, (x+17)(x+20) < 0
So,
x can equal -18 or -19Since we cannot answer the
target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined Statement 1 tells us that
x can equal -21, -20 or -19Statement 2 tells us that
x can equal -18 or -19Since both statements are TRUE, it
must be the case that
x = -19Since we can answer the
target question with certainty, the combined statements are SUFFICIENT
Answer: C
Cheers,
Brent