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Quote:
If x is a positive integer, what is the value of x?

(1) (6 - 2x)(6 - x) < 0
(2) (x - 5)(x + 7) < 0

x≥1 (posinteger)

(1) insufic
(6 - 2x)(6 - x) < 0, 2x^2-18x+36<0,
x^2-9x+18<0, (x-3)(x-6)<0,
3<x<6: x=4,5

(2) insufic
(x - 5)(x + 7) < 0,
-7<x<5, 0<x<5, x=1,2,3,4

(1/2) sufic
combined x=4

ans (C)
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The answer is C

From Statement 1
(x-6)(x-3)<0, therefore x is negative between 3-6 exclusive i.e. only two int values 4&5

From statement 2
(x-5)(x+7)<0, therefore x is negative between -7 to 5 exclusive, multiple +ve int values

combining both statements we get x=4
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IMO C

If x is a positive integer, what is the value of x?

(1) (6 - 2x)(6 - x) < 0

......+Ve ...... 3 ... -Ve ....... 6 ..... +Ve
So , 3< x < 6
Not sufficient

(2) (x - 5)(x + 7) < 0

.... +Ve....... -7 ..... -Ve ..... 5
So -7 < x < 5
Not Sufficient

Together: x= 4
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#1
(6 - 2x)(6 - x) < 0
solve for x we get
x^2-9x+18<0
x= 4,5
insufficient
#2
(x - 5)(x + 7) < 0
value of x = 1,2,3,4
sufficient
from 1 &2
x has to be +4
sufficient
OPTION C

If x is a positive integer, what is the value of x?

(1) (6 - 2x)(6 - x) < 0
(2) (x - 5)(x + 7) < 0
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If x is a positive integer, what is the value of x?

(1) (6 - 2x)(6 - x) < 0
(2) (x - 5)(x + 7) < 0

1) 3<x<6
x=4,5

2) -7<X<5
x=0,1,2,3,4,-6,...

1+2)
x=4
Ans C
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