Syumbel1
If y is an integer, is y a prime number of the form 4k-1, where k is a positive integer
1) (7y^9+6)^2/4 is an integer
2) (7y^5-222)^2/8 is a positive integer, which is neither prime nor composite
Sol:
Option-DIs y a prime number of the form 4k-1 : 3, 7, 11, ...
Stat-1:
\((7y^9+6)^2\)/4 is an integer , Therefore, \((7y^9+6)^2\) is divisible by 4 or
\((7y^9+6)^2\) = 4*p
4*p is an even number , therefore, \((7y^9+6)^2\) is even and square for a number is even only if the number is even.
This implies, \((7y^9+6)\) is even.
Odd*x + Even = Even and thus, y^9 is even. and y is even and can't be a prime of the form 4k-1
This statement is Sufficient.Stat-2: \((7y^5-222)^2\)/8 is a positive integer ; With same reasoning as in stat-1
\((7y^5-222)^2\) = 8*p
Odd*x-Even = Even , and thus, y^5 is even. and y is even and can't be a prime of the form 4k-1
This statement is also Sufficient.