NEW HERE? LEARN MORE
closeclose
Last visit was: 26 Apr 2024, 03:31 It is currently 26 Apr 2024, 03:31
Decision Tracker
My Rewards
New posts
New comers' posts

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel

In a game with one die, player X wins if the number of points on her

SORT BY:
Date
Kudos
Tags:
Find Similar Topics 
Show Tags
Hide Tags
User avatar
L
Bunuel
Math Expert
Joined: 02 Sep 2009
Posts: 92929
Own Kudos [?]: 619105 [3]
Given Kudos: 81609
Send PM
CAT Tests Forum Quiz Mode
In a game with one die, player X wins if the number of points on her [#permalink] New post   04 Feb 2021, 11:17
3
Bookmarks
Expert Reply
00:00
A
B
C
D
E

Difficulty:

55% (hard)

Question Stats:

54% (01:57) correct 46% (01:45) wrong based on 52 sessions
Hide Show timer Statistics
In a game with one die, player X wins if the number of points on her throw is greater than,or equal to, the number of points on player Y’s throw. The probability of X winning is:

(A) 1/2
(B) 19/36
(C) 13/24
(D) 7/12
(E) 2/3
ShowHide Answer
Official Answer
D
User avatar
P
gmatcafe
Manager
Manager
Joined: 27 Sep 2020
Posts: 191
Own Kudos [?]: 195 [0]
Given Kudos: 97
Location: Uzbekistan
Concentration: Finance, Strategy
Schools: Marshall '25 Smeal Carey Ross '25
GPA: 3.73
WE:Consulting (Consulting)
Send PM
Re: In a game with one die, player X wins if the number of points on her [#permalink] New post   04 Feb 2021, 11:54
There are 6*6=36 ways of choosing pairs of X and Y. Let's consider the number of ways in which Y may win. If Y=2, in order Y to win X must be 1. If Y=3, X must be be 1 or 2. If Y=4, X must be 1, 2 or 3 and so on:
Y:2 3 4 5 6
1 2 3 4 5
In 1+2+3+4+5=15 ways Y wins. In 36-15=21 ways X wins. 21/36=7/12 D)
User avatar
S
BAA5
Manager
Manager
Joined: 05 Jun 2021
Posts: 112
Own Kudos [?]: 75 [1]
Given Kudos: 77
GMAT 1: 750 Q49 V44
Send PM
Reviews Badge
In a game with one die, player X wins if the number of points on her [#permalink] New post   31 Oct 2021, 13:39
1
Bookmarks
Outcome of Y...................Probability of Y .............Probability of X

.......... 1 ................................1/6...........................6/6
.......... 2 ................................1/6 ..........................5/6
.......... 3 ................................1/6 ...........................4/6
.......... 4 ...............................1/6........................... 3/6
.......... 5 ................................1/6............................2/6
.......... 6 ................................1/6 ...........................1/6


Probability of X winning is (1/6)(6/6 + 5/6 + 4/6 +3/6 + 2/6 +1/6) = 21/36 = 7/12
User avatar
B
JerryAtDreamScore
Dream Score Representative
Joined: 07 Oct 2021
Posts: 391
Own Kudos [?]: 305 [0]
Given Kudos: 2
Send PM
Re: In a game with one die, player X wins if the number of points on her [#permalink] New post   31 Oct 2021, 16:52
Bunuel wrote:
In a game with one die, player X wins if the number of points on her throw is greater than,or equal to, the number of points on player Y’s throw. The probability of X winning is:

(A) 1/2
(B) 19/36
(C) 13/24
(D) 7/12
(E) 2/3


Breaking Down the Info:

There are \(6 * 6 = 36\) outcomes in total.

The probability of X and Y tying, would be \(\frac{6}{36} = \frac{1}{6}\).

We can divide the rest of the probability space in half as the probability of X throwing higher than Y is the same as the probability of Y throwing higher than X.

Then the probability of X getting a higher throw is \(\frac{5}{6}/2 = \frac{5}{12}\). Finally add \(\frac{1}{6}\) back as a tie counts as X winning.

\(\frac{5}{12} + \frac{2}{12} = \frac{7}{12}\).

Answer: D
GMAT Club Bot
gmatclubot
Re: In a game with one die, player X wins if the number of points on her [#permalink]
31 Oct 2021, 16:52
Moderators:
Bunuel
Math Expert
92929 posts
yashikaaggarwal
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne
Main navigation
GMAT Resources
Partners
MBA Resources
www.gmac.com|www.mba.com | | GMAT Club Rules | Terms and Conditions