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Re: In a group, the ratio of the number of women to the number of children [#permalink]
A - using this we get ratio 21:6:10 - insufficient
B - this dissent gives any clue about men

Combining A and B the only possibility we have is 12 children. Hence C.

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Re: In a group, the ratio of the number of women to the number of children [#permalink]
Women = 7x
Children = 2x

Men = y

(1) 2x:y = 3:5
We can't find y. Insufficient.

(2) 2x is between 10 and 15. So, 2x can be 10,12, or 14. Also, no information about men. Insufficient.

Combining,

From (1), we get:

2x:y = 3:5
So, y = 2x*5/3

Only the value of 2x = 12 makes y an integer.

So, y = 20. Hence sufficient.

C.
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Re: In a group, the ratio of the number of women to the number of children [#permalink]
I took my time with this question. I'd be really grateful if anyone could spill some secrets on how they did it under 2 minutes. MartyTargetTestPrep avigutman VeritasKarishma Bunuel

So:
Info:
women to the number of children/ W:C = 7:2

(1) The ratio of the number of children to the number of men is 3:5.
C:M = 3:5
we are given more ratio information w/o any absolute values, so insufficient. (Eliminate A,D)
(2) The number of children in the group is between 10 and 15.
The number of children is either 11,12,13, or 14
but from the info of the question, we know that the children are 2x. This means we can eliminate the odd numbers (i.e. 11,13)
here we are can solve no. of children to be either 6 or 7.
Insufficient as we are not getting a certain answer. Eliminate B.

Combining 1&2:
C:M = 3:5
No of children = 12 or 14

solving for both:
3x = 12
x= 12/3=4 (valid)

3x=14 (not divisible)

So the number of children is 12 and the multiplying factor is 3.

Do let me know if there is any error/disconnect. Thanks!
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Re: In a group, the ratio of the number of women to the number of children [#permalink]
avigutman wrote:
ritzu wrote:

(2) The number of children in the group is between 10 and 15.
The number of children is either 11,12,13, or 14
but from the info of the question, we know that the children are 2x. This means we can eliminate the odd numbers (i.e. 11,13)
here we are can solve no. of children to be either 6 or 7.
Insufficient as we are not getting a certain answer. Eliminate B.


“Between 10 and 15” may or may not include 10 and 15. The fact that they didn’t bother stating “inclusive” or “exclusive” implies that in this case it’s irrelevant. You’re correct that odd values can be eliminated. But a faster way to rule out sufficiency with this statement is the fact that we have no info about men, and the question is asking about men. I get the sense that you may have forgotten what exactly the question asked for.

ritzu wrote:
Combining 1&2:
C:M = 3:5
No of children = 12 or 14

solving for both:
3x = 12
x= 12/3=4 (valid)

3x=14 (not divisible)

So the number of children is 12 and the multiplying factor is 3.


We now have children represented by 2 ratio units in the free info and by 3 ratio units in statement 1, so we can conclude that the actual number of children is a multiple of 6. There’s only one multiple of 6 between 10 and 15, so we can now find any actual number we want. Men, women, or children.

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avigutman, Thank you for replying! It makes sense to me now. It's great getting your input especially after binging your videos on Ratios haha!
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Re: In a group, the ratio of the number of women to the number of children [#permalink]
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Re: In a group, the ratio of the number of women to the number of children [#permalink]
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