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Re: In a rectangle, the length is increased by 10%, and the width is decre [#permalink]
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Let the length of original rectangle be L and breadth be B
Area = L*B -----------(1)

Length of changed rectangle = 1.1*L
Breadth of changed rectangle = 0.9*B
Area = 1.1*L*0.9*B = 0.99*L*B

Reduced area of rectangle = original area - changed area
=L*B - 0.99*L*B => 0.01*L*B

The percentage change = 0.01*L*B*100/1 => 1

Answer is A

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Re: In a rectangle, the length is increased by 10%, and the width is decre [#permalink]
Expert Reply
=>

Assume \(a = AD\) and \(b = AB\) are the lengths of the two sides of rectangle \(ABCD\), as shown in the figure.

Then the area of the rectangle \(ABCD\) is \(ab.\)

Then the area of the rectangle \(AB’C’D’\) is \(a(1 - 0.1)·b(1 + 0.1) = ab(1 - 0.01)\) after the sides change.

Thus, the area is decreased by \(1%.\)

Therefore, A is the answer.
Answer: A
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Re: In a rectangle, the length is increased by 10%, and the width is decre [#permalink]
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