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# In a sequence of terms in which each term is three times the

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In a sequence of terms in which each term is three times the [#permalink]

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13 Oct 2009, 06:36
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In a sequence of terms in which each term is three times the previous term, what is the fourth term?

(1) The first term is 3.

(2) The second-to-last term is 3^10.

OPEN DISCUSSION OF THIS QUESTION IS HERE: in-a-sequence-of-terms-in-which-each-term-is-three-times-the-109374.html
[Reveal] Spoiler: OA

Last edited by Bunuel on 18 Dec 2013, 10:20, edited 2 times in total.
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Re: Tuesday Q1 - Fourth Term [#permalink]

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13 Oct 2009, 07:00
hogann wrote:
In a sequence of terms in which each term is three times the previous term, what is the fourth term?

(1) The first term is 3.

(2) The second-to-last term is 310.

If the 1st term is 3 then 2nd term will be 3*3 = 9 , 3rd term = 9*3 and 4th term is 9*3*3
so A is suf

310 is second to last but w/o the first term we cannot determine the number of terms hence B is insuf
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Re: In a sequence of terms in which each term is three times the [#permalink]

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18 Dec 2013, 09:42
hogann wrote:
In a sequence of terms in which each term is three times the previous term, what is the fourth term?

(1) The first term is 3.

(2) The second-to-last term is 3^10.

Cheers
J
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Re: In a sequence of terms in which each term is three times the [#permalink]

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18 Dec 2013, 10:21
In a sequence of terms in which each term is three times the previous term, what is the fourth term?

(1) The first term is 3 --> sequence is: 3, 9, 27, 81, ... so the fourth term is 81. Sufficient.

(2) The second-to-last term is 3^10 --> since we don't know how many terms are there in the sequence then we don't know which term is second-to-last. For example: if it's third term then fourth (and last) will be 3^11, if it's fifth term then the fourth term is 3^9, ... Not sufficient.

OPEN DISCUSSION OF THIS QUESTION IS HERE: in-a-sequence-of-terms-in-which-each-term-is-three-times-the-109374.html
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Re: In a sequence of terms in which each term is three times the   [#permalink] 18 Dec 2013, 10:21
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