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Re: In the addition above, #, @, and & each represent a distinct, positive [#permalink]
Why 0 and 6 values for # and is not considered in this question
Please explain

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In the addition above, #, @, and & each represent a distinct, positive [#permalink]
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saurabhrampal wrote:
Why 0 and 6 values for # and is not considered in this question
Please explain

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saurabhrampal

saurabhrampal questions say specifically distinct + ve integer, hence only 2,4 or 4,2 are possible we cannot have 0,6 and answer as 6 ...

In the addition above, #, @, and & each represent a distinct, positive digit

hope this helps

Originally posted by Archit3110 on 24 Dec 2018, 06:25.
Last edited by Archit3110 on 24 Dec 2018, 06:45, edited 1 time in total.
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Re: In the addition above, #, @, and & each represent a distinct, positive [#permalink]
But zero is an even number

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Re: In the addition above, #, @, and & each represent a distinct, positive [#permalink]
saurabhrampal wrote:
But zero is an even number

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yes , its an even integer..
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Re: In the addition above, #, @, and & each represent a distinct, positive [#permalink]
saurabhrampal wrote:
But zero is an even number

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zero is neither positive nor negative.
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In the addition above, #, @, and & each represent a distinct, positive [#permalink]
Had same question with whether or not 0 was a possibility. Question statement specifically says that #, @, & each represent a distinct, POSITIVE integer. Statement then further identifies & as even and then statement 1 says # and @ are also even.

This is tricky because you have to remember the initial question statement saying that all were positive integers. The rule for how the GMAT treats 0 is that 0 is considered an EVEN integer, but NOT a positive or negative integer. It is considered neither positive nor negative. But it is considered an even integer. So the only answer options were # = 2, @ = 4 or # = 4, @ = 2, but statement 2 identifies that # > @, so the answer is # = 4.

Hope that helps.
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In the addition above, #, @, and & each represent a distinct, positive [#permalink]
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