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In the diagram above, the fourteen rectangular tiles are all

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In the diagram above, the fourteen rectangular tiles are all [#permalink]

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In the diagram above, the fourteen rectangular tiles are all identical. What percent of the area of rectangle ABCD is covered by the tiles?

(1) ABCD is a square.

(2) EFGH is a square.
[Reveal] Spoiler: OA

Last edited by Bunuel on 04 Feb 2014, 02:22, edited 1 time in total.
Edited the question.

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Re: In the diagram above, the fourteen rectangular tiles are all [#permalink]

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nave81 wrote:
In the diagram above, the fourteen rectangular tiles are all identical. What percent of the area of rectangle ABCD is covered by the tiles?

(1) ABCD is a square.

(2) EFGH is a square.


Figure attached
Suppose the dimention of the tiles are l*b

STAT1
Let side of Square ABCD = a
then if you consider side AB then
AB = a = 3l + 2b

if you consider side AD then
AD = a = 4l

so, 4l = 3l + 2b
or, l =2b

Also, we know that a = 4l
so, l = a/4
b = l/2 = a/8
So, we can find the area of the tile in terms of "a"
Area of all the tiles = (constant)* a^2
So, we can find the percentage of area occupied by tile = ((constant)* a^2 / a^2 ) * 100
So, SUFFICIENT

STAT2
Let side of EFGH = c
then if you consider EF then
EF = c = 3l

if you consider EH then
EH = c = 2l + l-b + l-b = 4l-2b

=> 3l = 4l-2b
l = 2b

And we have c = 3l
=> l = c/3
b = l/2 = c/6

AB = 4l = 4c/3

So, we can find area of ABCD in terms of C And we can find area of the tiles in terms of c
So, we can find the percentage of area occupied by tiles
So, SUFFICIENT

Hence answer will be D

Hope it helps!
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Re: In the diagram above, the fourteen rectangular tiles are all [#permalink]

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New post 28 Mar 2013, 13:47
BUMP! Any quicker ways to solve this?
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Re: In the diagram above, the fourteen rectangular tiles are all [#permalink]

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manimgoindowndown wrote:
BUMP! Any quicker ways to solve this?


Statement 1 :
AB = BC as the figure is square
Hence 3l+2b = 4l ==> l=2b and 4l = S (S = side of the square)

% = (14*l*b) *100/S^2 ==> as you know all the relationships, you can make this one variable equation and get the answer.

Statement 2 :
EF = FG as the figure is square
Hence 3l = 2l + 2b ==> l=2b and 4l = S (S = side of the square)

% = (14*l*b) *100/S^2 ==> as you know all the relationships, you can make this one variable equation and get the answer.

Answer hence is D
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Re: In the diagram above, the fourteen rectangular tiles are all [#permalink]

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(1) SUFFICIENT: Let the length (longer dimension) of each rectangular tile be called L, and the width (shorter dimension) of each tile W. Then each horizontal side of square ABCD has total length 2W + 3L, and each vertical side has total length 4L.

Because ABCD is a square, these total lengths must be equal: 2W + 3L = 4L, which reduces to L = 2W. Therefore, each side of square ABCD is equal to 4L = 8W, and the total area of square ABCD is (8W)(8W) = 64W2.

The total area of the tiles is 14(L × W) = 14(2W × W) = 28W2. The desired fraction is thus (28W2)/(64W2) = 28/64. There is no need to reduce this fraction; the statement is sufficient.

(2) SUFFICIENT: Let the length (longer dimension) of each rectangular tile be called L, and the width (shorter dimension) of each tile W. Then each horizontal side of square ABCD has total length 3L, and each vertical side has total length 4L – 2W.

Because EFGH is a square, these total lengths must be equal: 3L = 4L – 2W, which reduces to L = 2W. Therefore, each side of square ABCD is equal to 3L = 6W.

In turn, ABCD must also be a square, since each of its sides is 2W longer than the corresponding side of EFGH (i.e., longer by W on each side). Therefore, each side of ABCD is equal to 6W + 2W = 8W, and the total area of square ABCD is (8W)(8W) = 64W2.

The total area of the tiles is 14(L × W) = 14(2W × W) = 28W2. The desired fraction is thus (28W2)/(64W2) = 28/64. There is no need to reduce this fraction; the statement is sufficient.

The correct answer is D.
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Re: In the diagram above, the fourteen rectangular tiles are all [#permalink]

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New post 08 Oct 2014, 01:43
Hey Bunuel,
could u please help me understand how to reach at an answer..am really unable to understand it..
thanks..
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Re: In the diagram above, the fourteen rectangular tiles are all [#permalink]

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New post 15 Dec 2017, 10:19
Okay, think of it like a real life problem. I have actually sort of seen this in floor tile designs:

n the diagram above, the fourteen rectangular tiles are all identical. What percent of the area of rectangle ABCD is covered by the tiles?

(1) ABCD is a square. - obvious, inner area is also a square due to identical difference between outer and inner square. As each side has 4 division, we get x/4; the smaller part of tile being x/8 (half of x/4). Suff

(2) EFGH is a square. - so outer part has to be a square. Again we reach the x/4 and x/8 combination

Sufficient.

Ans D

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Re: In the diagram above, the fourteen rectangular tiles are all   [#permalink] 15 Dec 2017, 10:19
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