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# In the figure above, if PQ is a line segment and PO = OQ, what are the

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Math Expert
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Posts: 55150
In the figure above, if PQ is a line segment and PO = OQ, what are the  [#permalink]

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15 Dec 2017, 02:13
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86% (00:39) correct 14% (01:07) wrong based on 69 sessions

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In the figure above, if PQ is a line segment and PO = OQ, what are the coordinates of Q?

(A) (s, r)
(B) (s, –r)
(C) (–s, –r)
(D) (–r, s)
(E) (–r, –s)

Attachment:

2017-12-15_1300.png [ 6.21 KiB | Viewed 1064 times ]

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In the figure above, if PQ is a line segment and PO = OQ, what are the  [#permalink]

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Updated on: 15 Dec 2017, 11:52
In the figure above, if PQ is a line segment and PO = OQ, what are the coordinates of Q?

(A) (s, r)
(B) (s, –r)
(C) (–s, –r)
(D) (–r, s)
(E) (–r, –s)

Attachment:
2017-12-15_1300.png
[/quote]

Q is in third Quad and any point in 3rd Quadrant both points are negative. So answer is E

Originally posted by kamilkhan on 15 Dec 2017, 04:35.
Last edited by kamilkhan on 15 Dec 2017, 11:52, edited 1 time in total.
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Joined: 12 Nov 2017
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Re: In the figure above, if PQ is a line segment and PO = OQ, what are the  [#permalink]

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15 Dec 2017, 05:16
Should be E. x coordinate -r, y coordinate -s
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Joined: 02 Aug 2009
Posts: 7671
Re: In the figure above, if PQ is a line segment and PO = OQ, what are the  [#permalink]

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15 Dec 2017, 06:42
Bunuel wrote:

In the figure above, if PQ is a line segment and PO = OQ, what are the coordinates of Q?

(A) (s, r)
(B) (s, –r)
(C) (–s, –r)
(D) (–r, s)
(E) (–r, –s)

Attachment:
2017-12-15_1300.png

Hi..

Ofcourse 3rd quadrant means that BOTH will be NEGATIVE..
So ans will be C or E..

Now draw a perpendicular on y axis from both P and Q..
Both triangles thus formed will be similar as all three angles are equal and PO =OQ
So the perpendicular drawn will be equal.... If it is s in 1st quadrant, it will be -s in III quadrant..
So -r,-s
E
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Re: In the figure above, if PQ is a line segment and PO = OQ, what are the  [#permalink]

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16 Feb 2019, 04:13
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Re: In the figure above, if PQ is a line segment and PO = OQ, what are the   [#permalink] 16 Feb 2019, 04:13
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