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Re: In the figure, the area of rectangle EFGH is 3 units greater than the [#permalink]
Bunuel wrote:

In the figure, the area of rectangle EFGH is 3 units greater than the area of rectangle ABCD. What is the value of ab if a + b = 8?

(A) 9
(B) 12
(C) 15
(D) 18
(E) 21

Attachment:
recs.jpg


\((x+a)(x+b) - (x+2)(x+6) = 3\)

Or, \((ab +ax + bx +x^2) - (x^2 +8x + 12) = 3\)

Or, \(ab + x (a + b) - 8x - 12 = 3\)

Or, \(ab + 8x - 8x - 12 = 3\)

Or, \(ab = 15\), Answer must be (C)
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Re: In the figure, the area of rectangle EFGH is 3 units greater than the [#permalink]


Formula used: Area(Rectangle) = Length * Breadth.
Given: Area(Rectangle EFGH) is 3 units greater than the Area(Rectangle ABCD)

Area(Rectangle ABCD) = \((x+2)(x+6) = x^2 + 8x + 12\) units.
Area(Rectangle EFGH) = \((x+a)(x+b) = x^2 + (a+b)x + ab\) units.

Therefore, the area of the rectangle ABCD is \((x^2 + 8x + 12) + 3 = x^2 + 8x + 15\) and value of ab is 15(Option C)
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Re: In the figure, the area of rectangle EFGH is 3 units greater than the [#permalink]
Expert Reply
Bunuel wrote:

In the figure, the area of rectangle EFGH is 3 units greater than the area of rectangle ABCD. What is the value of ab if a + b = 8?

(A) 9
(B) 12
(C) 15
(D) 18
(E) 21

Attachment:
recs.jpg


We can create the equation:

3 + (x + 2)(x + 6) = (x + a)(x + b)

3 + x^2 + 8x + 12 = x^2 + ax + bx + ab

15 + 8x = ax + bx + ab

15 + 8x = x(a + b) + ab

Since a + b = 8, we have:

15 + 8x = 8x + ab

15 = ab

Answer: C
GMAT Club Bot
Re: In the figure, the area of rectangle EFGH is 3 units greater than the [#permalink]
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