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Re: In the rectangular coordinate system above, if OB < BC then is the are [#permalink]
chetan2u wrote:
TARGET730 wrote:
Attachment:
download.png
In the rectangular coordinate system above, if OB < BC then is the area of the triangle ABC lesser than 12 square units?

(1) Point A lies above the line y = 5
(2) The mid-point of B and C is (6, 0)



hi target 730,

ans E.. FOR THIS QUESTION..
but just a point that each statement does convey a pertinant point..
1) statement 1 tells us that height is 5 or >5.. insufficient since the Q asks <12, we will take the lowest value of
2) statement 2 tells us the width, here it gives the lowest value for width to be 4... insufficient..
combined if we take the lowest value for area..1/2*5*4=10 ao area >10 so not sufficient

however if the coord were (8,0).. the lowest value of base would be 16/3..
so lowest area = 1/2*5*16/3 >12 so ans would be combined sufficient..

my point we have to read the values very minutely..


hi chetan2u,
I have a question in the second statement

As (6,0) [lets call it as X] is the midpoint of BC ,so BX=XC=BC/2 and you have taken the lowest value for width to be 4

so BX=XC=4/2=2
according to this B([6-2],0) and C([6+2],0)
which means B(4,0) and C(8,0)
this gives OB=BC=4
but in the stem it is given that OB<BC.
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Re: In the rectangular coordinate system above, if OB < BC then is the are [#permalink]
Hi all,
To calculate the area of the triangle we need base and the height here
That is we got to check
½ (BC)(height)<12?
1). Statement 1 is insufficient.
This talks only about height. This says height is greater than or equal to 5.
2). Statement 2 is insufficient.
This talks only about base which is BC. This says base length can be 6 or 8.
B(3.0) and C(9,0)
B(2,0) and C(10,0)
Together sufficient,
Height minimum we can take is 5 and base minimum can be 6. Then the area is 15.
Always the area going to be greater than 12.
Together sufficient.
So the answer is C.
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Re: In the rectangular coordinate system above, if OB < BC then is the are [#permalink]
CrackVerbalGMAT,

I think the answer is E. What if B is (3.9, 0) and C is (8.1,0) ? In this case BC = 4.2, which is greater than OB.

Area will be 10.5 which is less than 12
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Re: In the rectangular coordinate system above, if OB < BC then is the are [#permalink]
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CrackVerbalGMAT wrote:
Hi all,
To calculate the area of the triangle we need base and the height here
That is we got to check
½ (BC)(height)<12?
1). Statement 1 is insufficient.
This talks only about height. This says height is greater than or equal to 5.
2). Statement 2 is insufficient.
This talks only about base which is BC. This says base length can be 6 or 8.
B(3.0) and C(9,0)
B(2,0) and C(10,0)
Together sufficient,
Height minimum we can take is 5 and base minimum can be 6. Then the area is 15.
Always the area going to be greater than 12.
Together sufficient.
So the answer is C.


Hi CrackVerbalGMAT,

The prompt never states that the co-ordinates are integers and there are more possible values for the base of the triangle in Fact 2 than the 6 and 8 that you noted. If you try minimizing the base and the height of the triangle, you'll get the correct answer.

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Re: In the rectangular coordinate system above, if OB < BC then is the are [#permalink]
Expert Reply
vinyasgupta wrote:

hi chetan2u,
I have a question in the second statement

As (6,0) [lets call it as X] is the midpoint of BC ,so BX=XC=BC/2 and you have taken the lowest value for width to be 4

so BX=XC=4/2=2
according to this B([6-2],0) and C([6+2],0)
which means B(4,0) and C(8,0)
this gives OB=BC=4
but in the stem it is given that OB<BC.


hi vinay...

you are right that OB<BC....
however i have taken it as OB = BC because that is the value slightly above max value it can take and if it still does not satisfy the equation at slightly higher value than its max value, it will not satisfy at any other value..
also it is easier and faster to work with integer than x.9999 and other value as y.0001....
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Re: In the rectangular coordinate system above, if OB < BC then is the are [#permalink]
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