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# In the table above is shown the percent reduction in the

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Manager
Joined: 21 May 2011
Posts: 204
In the table above is shown the percent reduction in the  [#permalink]

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23 Jul 2011, 20:12
3
16
00:00

Difficulty:

95% (hard)

Question Stats:

38% (01:47) correct 62% (01:54) wrong based on 441 sessions

### HideShow timer Statistics

Date of Purchase
Percent Reduction

July 1 through July 7
5%

July 8 through July 14
30%

July 15 through July 21
55%

July 22 through July 28
70%

In the table above is shown the percent reduction in the price of every item in a store off the original price of that item on June 30 of that year. The table is for the 28 days immediately after June 30 of that year. If on July n of that year, Bill bought a suit that originally cost $450, what is the value of n? (1) Bill paid$112.50 less than he would have if he had bought it the day before.

From 2) if Bill paid $202.5 for the suit, you can figure out the week that particular sale price was on, but not the exact date. Hence, eliminate B. If both are true, it is easy to just pick the date which falls within the week from 2). Hence, C is correct. No math is required except 112.5/450 which is easy 25%. Hope this helps you. ##### General Discussion Senior Manager Joined: 24 Mar 2011 Posts: 354 Location: Texas Re: DS - 700 level - Suit [#permalink] ### Show Tags 23 Jul 2011, 20:27 interesting question.. i think i will choose A for this... only statement 1 is sufficient... how i solved? B - of course is sufficient..$202.50 .. falls under 3rd category BUT i dont know which day in 3rd category.. it can be any from july 15th through 21st...

now for A to be correct there is hint... to see if 55% of 450 - 30% of 450 = 112.50 and i think it is.
so it is the 15th day of july
Retired Moderator
Joined: 20 Dec 2010
Posts: 1810
Re: DS - 700 level - Suit  [#permalink]

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23 Jul 2011, 20:40
5
3
bschool83 wrote:
Date of Purchase
Percent Reduction

July 1 through July 7
5%

July 8 through July 14
30%

July 15 through July 21
55%

July 22 through July 28
70%

In the table above is shown the percent reduction in the price of every item in a store off the original price of that item on June 30 of that year. The table is for the 28 days immediately after June 30 of that year. If on July n of that year, Bill bought a suit that originally cost $450, what is the value of n? (1) Bill paid$112.50 less than he would have if he had bought it the day before.

(2) Bill paid $202.50 for the suit. Can't do much about it except solving: 1) 450*0.95=427.5 450*0.7=315 450*0.45=202.5 450*0.3=135.0 427.5-315=112.5 => n=8 315-202.5=112.5 => n=15 Not Sufficient. 2) 15<=n<=21 Not Sufficient. Together: n=15 Ans: "C" _________________ Manhattan Prep Instructor Joined: 22 Mar 2011 Posts: 1375 Re: DS - 700 level - Suit [#permalink] ### Show Tags 23 Jul 2011, 20:49 1 Fluke is right. This is a typical DS trap. If we see that a difference of 112.50 show up at the junction of two date ranges, we figure we have the answer and start congratulating ourselves. However, it's really important to check and see if there is more than one junction where that particular difference shows up. Assume that there will be, and you can be pleasantly surprised if you're wrong! _________________ Dmitry Farber | Manhattan GMAT Instructor | New York Manhattan GMAT Discount | Manhattan GMAT Course Reviews | View Instructor Profile | Manhattan GMAT Reviews VP Joined: 05 Mar 2015 Posts: 1003 Re: In the table above is shown the percent reduction in the [#permalink] ### Show Tags 15 Jun 2016, 09:09 bschool83 wrote: Date of Purchase Percent Reduction July 1 through July 7 5% July 8 through July 14 30% July 15 through July 21 55% July 22 through July 28 70% In the table above is shown the percent reduction in the price of every item in a store off the original price of that item on June 30 of that year. The table is for the 28 days immediately after June 30 of that year. If on July n of that year, Bill bought a suit that originally cost$450, what is the value of n?

(1) Bill paid $112.50 less than he would have if he had bought it the day before. (2) Bill paid$202.50 for the suit.

(1) insuff..because we don't know the discounted price/any price for which he would have paid $112.5. (2)202.5 is what percent less of 450... 450(1-x/100)=202.5 x=55% date "n" could be anything between july15-july21...not suff.... Combining both Bill paid$112.50 less than he would have if he had bought it the day before
means bill paid (202.5+112.5=\$315) if he bought with any previous discount a day before.
315 is 30% less than 450.
So he must bought on july 15
Ans C
Manager
Joined: 30 Mar 2017
Posts: 134
GMAT 1: 200 Q1 V1
Re: In the table above is shown the percent reduction in the  [#permalink]

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14 Jan 2018, 06:15
Algebraic approach:

Statement 1
Let $$x$$ be the discount Bill received and let $$y$$ be the previous period's discount. So we get this equation:
$$450(1-x) = 450(1-y) - 112.50$$
Which reduces to:
$$x-y = 0.25$$
This means that in the previous period, the discount was 25% less. Thus, Bill either bought his suit on July 8 or July 15. July 1 is not possible because there was no discount the day before. And July 22 is not possible because the discount was 15% less the day before.
Not sufficient.
Note that if the equation reduced to $$x-y = 0.15$$, Statement 1 alone would have been sufficient.

Statement 2
$$202.50 = 450(1-x)$$ where $$x$$ is the discount Bill received.
$$x = 0.55$$
So Bill could have bought his suit on any day July 15 through July 21.
Not sufficient.

Combining both statements
In Statement 1, we narrowed down the answer to July 8 or July 15.
In Statement 2, we narrowed down the answer to July 15 through July 21.
The only date common do both is July 15.
Sufficient.
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Joined: 09 Sep 2013
Posts: 9462
Re: In the table above is shown the percent reduction in the  [#permalink]

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17 Jan 2019, 12:58
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