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integers

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ritula
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integers [#permalink] New post   29 Jan 2009, 04:22
Pls explain ur answers



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Re: integers [#permalink] New post   29 Jan 2009, 05:35
For stmt2:

If x is even then y will also be even and since there are 24 integers in between, 12 of them will be odd. The same is true even if x is odd.

Thus stmt2 by itself is sufficient.

For stmt1:
If x is odd then then there will be 11 odd integers between x and y. However, if x is even then there will be 12 odd integers between x and y. Hence, insufficient.
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Re: integers [#permalink] New post   29 Jan 2009, 08:21
scthakur wrote:
For stmt2:

If x is even then y will also be even and since there are 24 integers in between, 12 of them will be odd. The same is true even if x is odd.

Thus stmt2 by itself is sufficient.

For stmt1:
If x is odd then then there will be 11 odd integers between x and y. However, if x is even then there will be 12 odd integers between x and y. Hence, insufficient.




I agree with Answer B.

Small correction. :If x is even then y will also be even -->wrong
If x is even then y will odd
If x is odd then y will even


to make life easier.. rephrase question (by replacing 24 with 4 and 12 with 2)
" since there are 24 integers in between, 12 of them will be odd"
with
" since there are 4 integers in between, 2 of them will be odd"

assume x is odd
x 2,3,4,5 y
1,2,3,4,5,6 --> only 3 and 5 are odd.
assume x is even

x,3,4,5,6,y
2,3,4,5,6,7 --> only 3 and 5 are odd.

Sufficient (B)

stat1 is not sufficient.
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Re: integers [#permalink] New post   29 Jan 2009, 10:30
Superb, u explained in such a simple way. Can u pls also explain how statement 1 is Insuff?
x2suresh wrote:
scthakur wrote:
For stmt2:

If x is even then y will also be even and since there are 24 integers in between, 12 of them will be odd. The same is true even if x is odd.

Thus stmt2 by itself is sufficient.

For stmt1:
If x is odd then then there will be 11 odd integers between x and y. However, if x is even then there will be 12 odd integers between x and y. Hence, insufficient.




I agree with Answer B.

Small correction. :If x is even then y will also be even -->wrong
If x is even then y will odd
If x is odd then y will even


to make life easier.. rephrase question (by replacing 24 with 4 and 12 with 2)
" since there are 24 integers in between, 12 of them will be odd"
with
" since there are 4 integers in between, 2 of them will be odd"

assume x is odd
x 2,3,4,5 y
1,2,3,4,5,6 --> only 3 and 5 are odd.
assume x is even

x,3,4,5,6,y
2,3,4,5,6,7 --> only 3 and 5 are odd.

Sufficient (B)

stat1 is not sufficient.
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Re: integers [#permalink] New post   30 Jan 2009, 00:19
Thanks for correction x2suresh.



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Re: integers [#permalink]
30 Jan 2009, 00:19
Moderator:
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