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29 Jan 2009, 04:22
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Pls explain ur answers
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29 Jan 2009, 05:35
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For stmt2:
If x is even then y will also be even and since there are 24 integers in between, 12 of them will be odd. The same is true even if x is odd.
Thus stmt2 by itself is sufficient.
For stmt1:
If x is odd then then there will be 11 odd integers between x and y. However, if x is even then there will be 12 odd integers between x and y. Hence, insufficient.
If x is even then y will also be even and since there are 24 integers in between, 12 of them will be odd. The same is true even if x is odd.
Thus stmt2 by itself is sufficient.
For stmt1:
If x is odd then then there will be 11 odd integers between x and y. However, if x is even then there will be 12 odd integers between x and y. Hence, insufficient.
29 Jan 2009, 08:21
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scthakur
I agree with Answer B.
Small correction. :If x is even then y will also be even -->wrong
If x is even then y will odd
If x is odd then y will even
to make life easier.. rephrase question (by replacing 24 with 4 and 12 with 2)
" since there are 24 integers in between, 12 of them will be odd"
with
" since there are 4 integers in between, 2 of them will be odd"
assume x is odd
x 2,3,4,5 y
1,2,3,4,5,6 --> only 3 and 5 are odd.
assume x is even
x,3,4,5,6,y
2,3,4,5,6,7 --> only 3 and 5 are odd.
Sufficient (B)
stat1 is not sufficient.
