Bunuel
stne
Why is this method not working?
from the stem |a-2| can be positive or negative
if |a-2| is negative then removing the mod we get -a+2 = b^2 - c^3 , so question becomes is -a+2= b^2-c^3 ?
or is a-2= c^3- b^2 ?
which is exactly what is given in statement 2 after rearranging statement (2)
so I thought (2) was sufficient. what is wrong with this method?
Thank you.
IF a-2 is negative (so IF a<2), the question is whether -(a – 2) = b^2 – c^3 ?
IF a-2 is non-negative (so IF a>=2), the question is whether a – 2 = b^2 – c^3 ?
From (1) the question becomes: is -(a – 2) = b^2 – c^3 ?
(2) says that -(a – 2) = b^2 – c^3. But we don't know whether a-2 is negative.
Combined we have all info needed.
Does this make sense?
Thank you , think I got it
Let me retry
Is |a – 2| = b^2 – c^3 ?
meaning
if a- 2 is positive then Is a-2 = b^2 – c^3? or if a-2 is negative then Is -a+2 = b^2-c^3?
Statement 2 says -a+2 = b^2- c^3 , but it doesn't tell us that a-2 is negative, if it had told us that a-2 is negative
and -a+2 = b^2- c^3 then it would have been sufficient
1+2
we know that a<2 so a- 2 is negative from 1
and -a+2 = b^2- c^3 from 2 hence we have all the info. tricky one
Have I got it ?