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Is A*B*C an odd integer? (1) A*B is an even integer (2) B*C is an even
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Bunuel
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Is A*B*C an odd integer? (1) A*B is an even integer (2) B*C is an even [#permalink] New post  25 Nov 2019, 01:23
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Is A*B*C an odd integer?

(1) A*B is an even integer
(2) B*C is an even integer

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Is A*B*C an odd integer? (1) A*B is an even integer (2) B*C is an even [#permalink] New post  25 Nov 2019, 01:27
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Bunuel wrote:
Is A*B*C an odd integer?

(1) A*B is an even integer
(2) B*C is an even integer

Are You Up For the Challenge: 700 Level Questions


#1
A*B is an even integer
A= 4 and B = 1/2 ; C is not know
insufficient
#2
B*C is an even integer
so B = 6 and C = 1/3 ; A not know
insufficient
from 1 &2
we cannot conclusively say which of A,B and C is fraction of integer
IMO E
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Bunuel
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Re: Is A*B*C an odd integer? (1) A*B is an even integer (2) B*C is an even [#permalink] New post  25 Nov 2019, 01:29
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Archit3110 wrote:
Bunuel wrote:
Is A*B*C an odd integer?

(1) A*B is an even integer
(2) B*C is an even integer

Are You Up For the Challenge: 700 Level Questions


#1
A*B is an even integer
so A*B*C not an odd integer
sufficient
#2
B*C is an even integer
so A*B*C not an odd integer
sufficient
IMO D


Aren't you missing something? Aren't you making an assumption which is not supported? After all, this is an 700-level question.
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Re: Is A*B*C an odd integer? (1) A*B is an even integer (2) B*C is an even [#permalink] New post  25 Nov 2019, 02:39
E --- Never given that A b and C are integers.

try A = 4 B = 1/2 and C= 8 , so yes ,,, the product is even
try A = 1/2 B = 4 and C=1/2 , so No,,,, the product is 1 , which is oDD



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Re: Is A*B*C an odd integer? (1) A*B is an even integer (2) B*C is an even [#permalink] New post  08 Jan 2020, 00:50
St 1 A*B= Even but C is not given it can be an integer or rational or irrational or decimal So Not sufficient

St 2 B*C= Even but A is not known it can be an integer or rational or irrational or decimal So Not sufficient

St1 + St2= Same Logic

So E is answer
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Re: Is A*B*C an odd integer? (1) A*B is an even integer (2) B*C is an even [#permalink] New post  28 Jul 2020, 09:26
I guess an easy way to deal with problems that don't specify if the numbers in question are integers is to substitute irrational numbers.

For eg., in this question, simply put in A=B=C= sq. root of 6. It will satisfy both statement 1 & 2 and still not be sufficient.
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