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Schools: Kenan-Flagler '18 (I) NUS '18 (I) Olin '18 (I) Leipzig FT"18 (A) Mason '18 (A$) Rotman '18 (D)
GMAT 1: 700 Q51 V33
Posts: 69
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
54% (02:16) correct
46%
(02:02)
wrong
based on 141
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Date
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Is a four digit number "abcd" divisible by 9?
(1) (a^b)(b^c) is divisible by 9
(2) (a+b)(c+d) is divisible by 9
(1) (a^b)(b^c) is divisible by 9
(2) (a+b)(c+d) is divisible by 9
PS: I dont know what is the level of this question. Experts are requested to rate this question in terms of its difficulty level.
PPS: Kudos needed if you find this question interesting.
Source - Koncepts of numbers by Gajendra Kumar
PPS: Kudos needed if you find this question interesting.
Source - Koncepts of numbers by Gajendra Kumar
12 Apr 2015, 12:02
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nailgmat2015
Is a four digit number "abcd" divisible by 9?
a) (a^b)*(b^c) is divisible by 9
b) (a+b) (c+d) is divisible by 9
PS: I dont know what is the level of this question. Experts are requested to rate this question in terms of its difficulty level.
PPS: Kudos needed if you find this question interesting.
Source - Koncepts of numbers by Gajendra Kumar
a) (a^b)*(b^c) is divisible by 9
b) (a+b) (c+d) is divisible by 9
PS: I dont know what is the level of this question. Experts are requested to rate this question in terms of its difficulty level.
PPS: Kudos needed if you find this question interesting.
Source - Koncepts of numbers by Gajendra Kumar
Update: wrong explanation.
1) if a = 3 and b =2 than \((a^b)*(b^c)\) is divisible by 9 but ABCD can be divisible if CD have 3 in factors or no if CD don't have 3 in factors
Insuffisient
2) if a = 7 and b = 2 than \((a+b)(c+d)\) is divisible by 9 but ABCD can be divisible if CD have 9 in factors or no if CD don't have 9 in factors
1+2) if a = 3, b = 2, c = 2, d = 7
\((a^b)*(b^c) = 3^2*2^2=18\) is divisible by 9
\((a+b)*(c+d) = (3+2)*(2+7)=45\) is divisible by 9
\(ABCD = 3*2*2*7 = 84\) is not divisible by 9
if a = 3, b = 3, c = 3, d = 3
\((a^b)*(b^c) = 3^3*3^3=729\) is divisible by 9
\((a+b)*(c+d) = (3+3)*(3+3)=36\) is divisible by 9
\(ABCD = 3*3*3*3 = 81\) is divisible by 9
Insufficient
Answer is E
Insuffisient
2) if a = 7 and b = 2 than \((a+b)(c+d)\) is divisible by 9 but ABCD can be divisible if CD have 9 in factors or no if CD don't have 9 in factors
1+2) if a = 3, b = 2, c = 2, d = 7
\((a^b)*(b^c) = 3^2*2^2=18\) is divisible by 9
\((a+b)*(c+d) = (3+2)*(2+7)=45\) is divisible by 9
\(ABCD = 3*2*2*7 = 84\) is not divisible by 9
if a = 3, b = 3, c = 3, d = 3
\((a^b)*(b^c) = 3^3*3^3=729\) is divisible by 9
\((a+b)*(c+d) = (3+3)*(3+3)=36\) is divisible by 9
\(ABCD = 3*3*3*3 = 81\) is divisible by 9
Insufficient
Answer is E
14 May 2015, 20:49
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Harley1980
nailgmat2015
Is a four digit number "abcd" divisible by 9?
a) (a^b)*(b^c) is divisible by 9
b) (a+b) (c+d) is divisible by 9
PS: I dont know what is the level of this question. Experts are requested to rate this question in terms of its difficulty level.
PPS: Kudos needed if you find this question interesting.
Source - Koncepts of numbers by Gajendra Kumar
a) (a^b)*(b^c) is divisible by 9
b) (a+b) (c+d) is divisible by 9
PS: I dont know what is the level of this question. Experts are requested to rate this question in terms of its difficulty level.
PPS: Kudos needed if you find this question interesting.
Source - Koncepts of numbers by Gajendra Kumar
1) if a = 3 and b =2 than \((a^b)*(b^c)\) is divisible by 9 but ABCD can be divisible if CD have 3 in factors or no if CD don't have 3 in factors
Insuffisient
2) if a = 7 and b = 2 than \((a+b)(c+d)\) is divisible by 9 but ABCD can be divisible if CD have 9 in factors or no if CD don't have 9 in factors
1+2) if a = 3, b = 2, c = 2, d = 7
\((a^b)*(b^c) = 3^2*2^2=18\) is divisible by 9
\((a+b)*(c+d) = (3+2)*(2+7)=45\) is divisible by 9
\(ABCD = 3*2*2*7 = 84\) is not divisible by 9
if a = 3, b = 3, c = 3, d = 3
\((a^b)*(b^c) = 3^3*3^3=729\) is divisible by 9
\((a+b)*(c+d) = (3+3)*(3+3)=36\) is divisible by 9
\(ABCD = 3*3*3*3 = 81\) is divisible by 9
Insufficient
Answer is E
Hi Harley, I think you misinterpreted the stem
the q is
Is a four digit number "abcd" divisible by 9?
(1) (a^b)(b^c) is divisible by 9
(2) (a+b)(c+d) is divisible by 9
so the task should be the sum of the digits a+b+c+d should be multiple of 9
as said by you "
if a = 3, b = 3, c = 3, d = 3
\((a^b)*(b^c) = 3^3*3^3=729\) is divisible by 9
\((a+b)*(c+d) = (3+3)*(3+3)=36\) is divisible by 9
\(ABCD = 3*3*3*3 = 81\) is divisible by 9
3333 sum 12 is not divisible by 9
However testing different values the OA is still E, It took more then 7-8 minutes for testing values by substitution , Bunuel ne elegant solution plz??
