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71% (01:05) correct
29%
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Is k the square of an integer?
(1) \(k= t^2 * q^6 *r^{10}\), where t, q and r are integers
(2) \(k= t^2 * m^{15}\), where t and m are integers
(1) \(k= t^2 * q^6 *r^{10}\), where t, q and r are integers
(2) \(k= t^2 * m^{15}\), where t and m are integers
19 Dec 2012, 03:05
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Is k the square of an integer?
We need to determine whether k is a perfect square.
(1) k = t^2*q^6*r^10, where t, q, and r are integers --> \(k=(tq^3r^5)^2=integer^2\). Sufficient.
(2) k = t^2*m^15, where t and m are integers --> if m is a perfect square itself (say if m=n^2 for some integer n), then k will also be a perfect square but if m is NOT a perfect square, then k also will NOT be a perfect square. For example consider m=1 and m=2. Not sufficient.
Answer: A.
We need to determine whether k is a perfect square.
(1) k = t^2*q^6*r^10, where t, q, and r are integers --> \(k=(tq^3r^5)^2=integer^2\). Sufficient.
(2) k = t^2*m^15, where t and m are integers --> if m is a perfect square itself (say if m=n^2 for some integer n), then k will also be a perfect square but if m is NOT a perfect square, then k also will NOT be a perfect square. For example consider m=1 and m=2. Not sufficient.
Answer: A.
General Discussion
18 Dec 2012, 23:18
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jsphcal
Is k the square of an integer?
(1) \(k= t ^2 * q^6 * r^10\) , where t, q and r are integers
(2) \(k= r ^2 * m^{15}\) , where r and m are integers
(1) \(k= t ^2 * q^6 * r^10\) , where t, q and r are integers
(2) \(k= r ^2 * m^{15}\) , where r and m are integers
Please correct the typo in statement 1...
1) we have\(k={(tq^3r^5)}^2\). Since t,q and r are intergers, k is the square of an integer. Sufficient.
2)m can take several values for k to not be the square of an integer. If m =1, k is the square of an integer. Insufficient.
Answer is A.
