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Is n < 0 ?
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Updated on: 06 May 2014, 01:12
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65% (00:56) correct 35% (00:49) wrong based on 204 sessions
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Is n < 0 ? (1) m < n (2) n < m My answer says, it would be C, although some expert says it will be E. Could anyone please advice ! Thanks in advance.
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Originally posted by nayasnayas on 05 May 2014, 20:29.
Last edited by Bunuel on 06 May 2014, 01:12, edited 1 time in total.
Renamed the topic and edited the question.



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Re: Is n < 0 ?
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06 May 2014, 01:20



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Re: a small doubt
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06 May 2014, 03:48
Even i feel answer should be C , as from a) n> m and from b) n>m, if we combine both the statements n can never be negative. We can pick some values and check . 1. n and m are positive numbers : n= 2 , m=1 here 2>1 and 2>1 > n is positive 2. n and m are negative numbers : n = 1 , m = 2 here 1 > 2 and 1 > 2 (not possible ) > n cannot be negative 3. n is positive or 0 and m is 0 or negative number : n =1 , m = 1 here 1> 1 and 1 > 1 (not possible ) ; n=1 , m = 0 here 1>0 and 1>0 > n is positive ; n=0 , m = 1 here 0 > 1 and 0 > 1(not possible ) 4. n is negative and m is positive > Not possible



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Re: Is n < 0 ?
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17 Nov 2015, 05:01
Bunuel wrote: nayasnayas wrote: Is n < 0 ? (1) m < n (2) n < m My answer says, it would be C, although some expert says it will be E. Could anyone please advice ! Thanks in advance. Is n < 0 ?(1) m < n. n is greater than some number m. This is clearly insufficient to say whether n is negative. Not sufficient. (2) n < m > 0 < m + n. The sum of n and some number m is positive. This is also insufficient to say whether n is negative. Not sufficient. (1)+(2) We can sum the inequalities with the signs in the same direction: m + (n) < n + m > 2n > 0 > n > 0. Sufficient. Answer: C. Hope it helps. Hey Bunuel, I totally understand the explanation, but have one doubt. If we put values in the equations my observation is coming out a little different please correct me where I am wrong. 1. m<n m=2; n=8; 2. n<m m=2; n= 8; Adding 1 and 2 we get n<m<n; or 8<2<8; So by just considering n as +ve value both conditions can be satisfied. Please correct me where I am wrong



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Re: Is n < 0 ?
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17 Nov 2015, 08:52
aby0007 wrote: Bunuel wrote: nayasnayas wrote: Is n < 0 ? (1) m < n (2) n < m My answer says, it would be C, although some expert says it will be E. Could anyone please advice ! Thanks in advance. Is n < 0 ?(1) m < n. n is greater than some number m. This is clearly insufficient to say whether n is negative. Not sufficient. (2) n < m > 0 < m + n. The sum of n and some number m is positive. This is also insufficient to say whether n is negative. Not sufficient. (1)+(2) We can sum the inequalities with the signs in the same direction: m + (n) < n + m > 2n > 0 > n > 0. Sufficient. Answer: C. Hope it helps. Hey Bunuel, I totally understand the explanation, but have one doubt. If we put values in the equations my observation is coming out a little different please correct me where I am wrong. 1. m<n m=2; n=8; 2. n<m m=2; n= 8; Adding 1 and 2 we get n<m<n; or 8<2<8; So by just considering n as +ve value both conditions can be satisfied. Please correct me where I am wrong Sorry your question is not clear... Also, I guess you meant n = 8 not n = 8 on (2)...
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Re: Is n < 0 ?
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17 Nov 2015, 09:54
Is n < 0 ?
(1) m < n. n is greater than some number m. This is clearly insufficient to say whether n is negative. Not sufficient.
(2) n < m > 0 < m + n. The sum of n and some number m is positive. This is also insufficient to say whether n is negative. Not sufficient.
(1)+(2) We can sum the inequalities with the signs in the same direction: m + (n) < n + m > 2n > 0 > n > 0. Sufficient.
Answer: C.
Hope it helps.
Hey Bunuel,
I totally understand the explanation, but have one doubt. If we put values in the equations my observation is coming out a little different please correct me where I am wrong.
1. m<n
m=2; n=8;
2. n<m
m=2; n= 8;
Adding 1 and 2 we get n<m<n;
or
8<2<8;
So by just considering n as +ve value both conditions can be satisfied. Please correct me where I am wrong[/quote]
Sorry your question is not clear... Also, I guess you meant n = 8 not n = 8 on (2)...[/quote]
Hey Bunuel,
Never mind I got it now.
Thanks.



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Re: Is n < 0 ?
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19 Oct 2017, 00:39
(1) m < n .. obviously not sufficient
(2) n < m.. not sufficient but if we multiply both sides by 1 we get n > m
Combine the two statements: n is greater than both m and m. So obviously 'n' can be neither 0 nor less than 0 (if n is zero it cannot be simultaneously greater than positive and negative of another number. If n is less than 0 then it will obviously be less than whichever out of m and m is positive). So n is > 0. Sufficient to answer. So C answer



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Re: Is n < 0 ?
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20 Nov 2018, 09:41
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