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Even i feel answer should be C , as from a) n> m and from b) n>-m, if we combine both the statements n can never be negative. We can pick some values and check . 1. n and m are positive numbers :- n= 2 , m=1 here 2>1 and 2>-1 -> n is positive 2. n and m are negative numbers :- n = -1 , m = -2 here -1 > -2 and -1 > 2 (not possible ) -> n cannot be negative 3. n is positive or 0 and m is 0 or negative number :- n =1 , m = -1 here 1> -1 and 1 > 1 (not possible ) ; n=1 , m = 0 here 1>0 and 1>0 -> n is positive ; n=0 , m = -1 here 0 > -1 and 0 > 1(not possible ) 4. n is negative and m is positive -> Not possible

My answer says, it would be C, although some expert says it will be E.

Could anyone please advice !

Thanks in advance.

Is n < 0 ?

(1) m < n. n is greater than some number m. This is clearly insufficient to say whether n is negative. Not sufficient.

(2) -n < m --> 0 < m + n. The sum of n and some number m is positive. This is also insufficient to say whether n is negative. Not sufficient.

(1)+(2) We can sum the inequalities with the signs in the same direction: m + (-n) < n + m --> 2n > 0 --> n > 0. Sufficient.

Answer: C.

Hope it helps.

Hey Bunuel,

I totally understand the explanation, but have one doubt. If we put values in the equations my observation is coming out a little different please correct me where I am wrong.

1. m<n

m=2; n=8;

2. -n<m

m=2; n= -8;

Adding 1 and 2 we get -n<m<n;

or

-8<2<8;

So by just considering n as +ve value both conditions can be satisfied. Please correct me where I am wrong

My answer says, it would be C, although some expert says it will be E.

Could anyone please advice !

Thanks in advance.

Is n < 0 ?

(1) m < n. n is greater than some number m. This is clearly insufficient to say whether n is negative. Not sufficient.

(2) -n < m --> 0 < m + n. The sum of n and some number m is positive. This is also insufficient to say whether n is negative. Not sufficient.

(1)+(2) We can sum the inequalities with the signs in the same direction: m + (-n) < n + m --> 2n > 0 --> n > 0. Sufficient.

Answer: C.

Hope it helps.

Hey Bunuel,

I totally understand the explanation, but have one doubt. If we put values in the equations my observation is coming out a little different please correct me where I am wrong.

1. m<n

m=2; n=8;

2. -n<m

m=2; n= -8;

Adding 1 and 2 we get -n<m<n;

or

-8<2<8;

So by just considering n as +ve value both conditions can be satisfied. Please correct me where I am wrong

Sorry your question is not clear... Also, I guess you meant n = 8 not n = -8 on (2)...
_________________

(1) m < n. n is greater than some number m. This is clearly insufficient to say whether n is negative. Not sufficient.

(2) -n < m --> 0 < m + n. The sum of n and some number m is positive. This is also insufficient to say whether n is negative. Not sufficient.

(1)+(2) We can sum the inequalities with the signs in the same direction: m + (-n) < n + m --> 2n > 0 --> n > 0. Sufficient.

Answer: C.

Hope it helps.

Hey Bunuel,

I totally understand the explanation, but have one doubt. If we put values in the equations my observation is coming out a little different please correct me where I am wrong.

1. m<n

m=2; n=8;

2. -n<m

m=2; n= -8;

Adding 1 and 2 we get -n<m<n;

or

-8<2<8;

So by just considering n as +ve value both conditions can be satisfied. Please correct me where I am wrong[/quote]

Sorry your question is not clear... Also, I guess you meant n = 8 not n = -8 on (2)...[/quote]

(2) -n < m.. not sufficient but if we multiply both sides by -1 we get n > -m

Combine the two statements: n is greater than both m and -m. So obviously 'n' can be neither 0 nor less than 0 (if n is zero it cannot be simultaneously greater than positive and negative of another number. If n is less than 0 then it will obviously be less than whichever out of m and -m is positive). So n is > 0. Sufficient to answer. So C answer