rockroars wrote:
But if you combine 1 and 2 wont we have 3 solutions?? They are 9, -9 and 5.
How does combining 1 and 2 eliminate the other two solutions -9 and 5?
On the GMAT, two data sufficiency statements always provide TRUE information and these statements never contradict each other.
From (1) we have that \(x=9\) OR \(x=-9\);
From (2) we have that \(x=9\) OR \(x=5\).
In order BOTH statements to be true x must be 9 only. In other words -5 can not be the value of \(x\) as \(x=-5\) doesn't satisfy \(x^2=81\), the same for -9, it can not be the value of \(x\) as \(x=-9\) doesn't satisfy \((x-9)(x-5)=0\).
In DS questions when you have some values for an unknown from (1) and (2) then when you consider (1)+(2) you will have that given unknown can take only intersection of these values (common values, common range).
For example: Is -1<x<1?
(1) x>0, not sufficient.
(2) x<1/2, not sufficient.
(1)+(2) Intersection of the ranges from (1) and (2) is 0<x<1/2, so the answer is YES. Sufficient.
Answer: C.
Alternately you can solve the original question as follows: from (1) \(x^2=81\) and from (2) \((x-9)(x-5)=x^2-14x+45=0\) --> \(x^2-14x+45=81-14x+45=0\) --> \(14x=126\) --> \(x=9\).
Hope it's clear.