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# Is x > y? (1) x/2 = y - 3 (2) y > 6

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Re: Is x > y? (1) x/2 = y - 3 (2) y > 6 [#permalink]
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Kudos
statement 1: x/2 = y-3 meaning x=2y-6. This is insufficient because y can take infinite values some which will be less than x while other possible values of y can be greater than x.

Statement 2: y>6. Clearly insufficient because no information is provided to enable us determine x.

1+2: sufficient because combining both statements means that all possible values of x will be greater than 6, hence we can conclusively stay that x>y.

The answer is C.
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Re: Is x > y? (1) x/2 = y - 3 (2) y > 6 [#permalink]
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Kudos
Is x > y ?

STATEMENT (1) - $$\frac{x}{2}$$ = y-3

y = $$\frac{x+6}{2}$$
if x = 8 then y = 7---is x>y?---YES
if x = 5 then y = 5.5---is x>y?---NO

STATEMENT (2) - y>6
no information is given about x
so, INSUFFICIENT

combining both statements

x = 2y-6 and y>6

if y = 6.1 then x = 6.2 ---x>y
any value of y > 6 will yield value of x that will be > y

hence, Is x>y -- the answer is YES
SUFFICIENT

C is the correct answer
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Re: Is x > y? (1) x/2 = y - 3 (2) y > 6 [#permalink]
Is x > y?

(1) $$\frac{x}{2} = y − 3$$
x = 0 → y = 3, x > y NO
x = 10 → y = 8, x > y YES
INSUFFICIENT.

(2) y > 6
No information about x.
INSUFFICIENT.

Together 1) and 2)
y = 6.1 → x = 6.2, x > y YES
y = 10 → x = 14, x > y YES

SUFFICIENT.

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Re: Is x > y? (1) x/2 = y - 3 (2) y > 6 [#permalink]
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Quote:
Is x>y?

(1) x/2=y−3
(2) y>6

(1) x/2=y-3…x-2y=-6…x=-6+2y; substitute, $$x>y…-6+2y>y…y>6$$? insufic.
(2) y>6: no info about $$x$$, insufic.
(1&2) y>6, true, sufic.