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Re: The sum of the two digit numbers above is a three digit number PQ5, wh [#permalink]
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QUESTION #1:

_X Y
+Y X
________

The sum of the two digit numbers above is a three digit number PQ5, where each letter X, Y, P, and Q represents a different non zero digit. Which of the following can be the value of X?

I) 7
II) 8
III) 9

(A) I only
(B) II only
(C) III only
(D) I and II only
(E) I , II and III




_X Y
+Y X
________


X+Y = 5

Possible values of x and Y are (X,Y)

(1,4)
(2,3)
(3,2)
(4,1)


The above pair can not produce 3 digit distinct numbers when they are added, hence we neglect these options.

(6,9)
(7,8)
(8,7)
(9,6)


The sum of the two digit numbers above is a three digit number PQ5

_X Y
+Y X
________

Check for the possible options -

(6,9)

69+96 = 165

(7,8)

78+87 = 165

(8,7)

87+78 = 165

(9,6)

96 + 69 = 165

Given the conditions only the folowing set of numbers product 3 digit distinct numbers in the form of PQ5 and the sum of its units digit is 5

(6,9)
(7,8)
(8,7)
(9,6)

So, the possible values of X can be 6,7,8 and 9.

Among the given options all 7 ,8 & 9 ca be the possible values of X.

Hence IMHO answer is (E) all 1,2 and 3.
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Re: The sum of the two digit numbers above is a three digit number PQ5, wh [#permalink]
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X Y
Y X
_______
PQ5

Here both the two digit numbers are made of x & y.

So, value of x+y can only be 15. [as none of x & y is 0 and unit digit of 3-digit sum is 5]

Let's try out the value of x with 3 given options.

x + y = sum of digits ......>> sum of both numbers
7 + 8 = 15 ..................>> 78 + 87 = 165
8 + 7 = 15 ..................>> 87 + 78 = 165
9 + 6 = 15 ..................>> 96 + 69 = 165 !!! x, y, p & q all should be different digit. NOT acceptable

Thus only two values [7 & 8] for x satisfy the condition.

Option (D) is correct.

Originally posted by musunna on 07 Nov 2015, 13:39.
Last edited by musunna on 08 Nov 2015, 03:53, edited 1 time in total.
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Re: The sum of the two digit numbers above is a three digit number PQ5, wh [#permalink]
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D: I and II only.
Easy to realize that P must be 1 because maximum 99+99 = 198 < 200, P cannot be 2 or greater.
XY + YX = 10X + Y + 10Y + X = 11(X+Y) = 1Q5
=> 1Q5 divisible by 11
=> Q = 1+5 = 6, PQ5 = 165
=> X+Y = 15 => (X,Y) e {(9,6),(8,7),(7,8),(6,9)}. But notice that X,Y,P,Q is different from each other so we cannot take 6 twice.
Conclusion : X e (7,8). Choice D.
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Re: The sum of the two digit numbers above is a three digit number PQ5, wh [#permalink]
Expert Reply
Bunuel wrote:

Jamboree and GMAT Club Contest Starts



QUESTION #1:

X Y
+Y X
________

The sum of the two digit numbers above is a three digit number PQ5, where each letter X, Y, P, and Q represents a different non zero digit. Which of the following can be the value of X?

I) 7
II) 8
III) 9

(A) I only
(B) II only
(C) III only
(D) I and II only
(E) I , II and III


Check conditions below:


For the following two weekends we'll be publishing 4 FRESH math questions and 4 FRESH verbal questions per weekend.

To participate, you will have to reply with your best answer/solution to the new questions that will be posted on Saturday and Sunday at 9 AM Pacific.
Then a week later, respective forum moderators will be selecting 2 winners who provided most correct answers to the questions, along with best solutions. Those winners will get 6-months access to GMAT Club Tests.

PLUS! Based on the answers and solutions for all the questions published during the project ONE user will be awarded with ONE Grand prize. He/She can opt for one of the following as a Grand Prize. It will be a choice for the winner:
-- GMAT Online Comprehensive (If the student wants an online GMAT preparation course)
-- GMAT Classroom Program (Only if he/she has a Jamboree center nearby and is willing to join the classroom program)

Bookmark this post to come back to this discussion for the question links - there will be 2 on Saturday and 2 on Sunday!



There is only one Grand prize and student can choose out of the above mentioned too options as per the conditions mentioned in blue font.
All announcements and winnings are final and no whining :-) GMAT Club reserves the rights to modify the terms of this offer at any time.


NOTE: Test Prep Experts and Tutors are asked not to participate. We would like to have the members maximize their learning and problem solving process.

Thank you!



JAMBOBREE OFFICIAL SOLUTION:

Since XY and YX are 2 digit numbers, there sum has to be less than 200. Thus, P = 1. Also sum of the digits X and Y should end with 5. Hence X + Y = 5 or 15 or 25… so that 5 is the units digit and tens digit is carried over. However, X + Y is less than 18 (as they are digits) and greater than 10 (else sum won’t be a 3-digit number). Thus, X + Y = 15, which gives
X Y
+ Y X
-------
P Q 5
=> 1 6 5

Alternatively: when a two digit number is added to another two digit number formed by reversing the digits of the first two digit number,the result is a multiple of 11. So in this case as PQ5 has to be a multiple of 11. So, using the divisibility rule of 11, P =1 and Q = 6.

Now, X+Y = 15,so all possible values of x and Y are
Case 1 X = 6 Y = 9
Case 2 X = 7 Y = 8
Case 3 X = 8 Y =7
Case 4 X =9 Y = 6

But as it is given that each letter X, Y, P, and Q represents a different non zero digit AND we know that Q = 6 so case 1 and case 4 are not possible

So the only possible values of x are 7 and 8

Hence the correct answer is option D.
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Re: The sum of the two digit numbers above is a three digit number PQ5, wh [#permalink]
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