VeritasPrepKarishma wrote:

Since speeds of the two are constant, we can directly use variation here.

Since Jane covers a gap of 4.75m by running 99.75m, she will cover a gap of 0.25 m by running another (99.75) x 0.25/4.75 = 5.25 m.

In races questions, making a diagram can give you a clear picture.

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Hi Karishma,

Can you please check where is my understanding going wrong. I got 5 as my answer. And here is how I arrived to this number

Let SJ -> speed of jane

SK-> speed of Karen

Now, since the time in which karen covers 95m is equal to time in which jane covers 99.75m,

we get,

95/sk = 99.75/sj -----> I

Also, let x be the distance from the 100m finish line in which jane overtakes karen. So,

(100+x)/sj = (95+x)/sk ------>II

solving I & II, we get,

x = 5, which is the desired answer