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Re: Jenny has 228 more marbles than Jack. If Bob gives each of them 133 ma [#permalink]
Let
No.of marbles John have = x
No.of marbles Jenny have = x+228

Bob gave 133 each to Jack (Jk) and Jenny(Jn).

No.of marbles(JK)= x+133
No.of marbles(Jn)= x+228+133=x+361

No.of marbles Jn= 2*(No.of marbles JK)

X+361=2*(x+133)
X+361=2x+266

Solving eqtn
2x-x=361-266

X=95= No.of marbles Jack

No.of marbles Jenny=95+228 =323

ANWSER- Opt - D

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Re: Jenny has 228 more marbles than Jack. If Bob gives each of them 133 ma [#permalink]
Jenny has 228 more marbles than Jack, so option A and B are out.

Between C, D and E, only 323 is odd and adding 133 to it can give an even number which can be twice of an integer value, so C and E are out as well.

Hence, answer is D.
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Re: Jenny has 228 more marbles than Jack. If Bob gives each of them 133 ma [#permalink]
Expert Reply
Bunuel wrote:
Jenny has 228 more marbles than Jack. If Bob gives each of them 133 marbles, Jenny will have twice as many marbles as Jack. How many marbles does Jenny have now?

A. 95
B. 190
C. 228
D. 323
E. 456


"Jenny has 228 more marbles...How many marbles does Jenny have now?" Well, A and B are out!!
We are left with C, D, and E. Let's just try D. If we need something smaller, it's C; if larger, E.
Jenny has 323. Jack has 95. 323+133=456. 95+133=228. Is 456 twice as many as 228? Yep.

Answer choice D.


ThatDudeKnowsPITA
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Re: Jenny has 228 more marbles than Jack. If Bob gives each of them 133 ma [#permalink]
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