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Jerry took a total of 10 tests, some in June and some in July last yea

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Sajjad1994
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Jerry took a total of 10 tests, some in June and some in July last yea [#permalink] New post   28 Dec 2020, 01:16
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Jerry took a total of 10 tests, some in June and some in July last year. What was the average (arithmetic mean) of the scores of the 10 tests that Jerry took in June and July last year?

(1) The average score of the tests Jerry took in June last year was 80.

(2) The average score of the tests Jerry took in July last year was 60.
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Deva0
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Re: Jerry took a total of 10 tests, some in June and some in July last yea [#permalink] New post   31 Dec 2020, 03:45
Since we can not determine how many tests were taken in june and july seperately, we can also not determine the mean for all 10 tests.

For example: if the mean of 3 tests in june was 80 and the mean of the remaining 7 in july was 60, the mean would be different than, let's say, if in both months 5 tests were taken.

Hence, E
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Re: Jerry took a total of 10 tests, some in June and some in July last yea [#permalink] New post   31 Dec 2020, 05:20
In both the statements we are given only the avg score per month. But we do not know the split of 10 tests, per month.
So no specific value can be derived.

Straight up option E.
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Re: Jerry took a total of 10 tests, some in June and some in July last yea [#permalink] New post   20 Jan 2021, 12:21
why cant we take an average of the average? 80+60 divided by 2?
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Jerry took a total of 10 tests, some in June and some in July last yea [#permalink] New post   20 Jan 2021, 14:38
Hi, KrishKapoor
KrishKapoor wrote:
why cant we take an average of the average? 80+60 divided by 2?


We can do it only if it was mentioned that Jerry took equal number of tests with scores of 80 & 60 respectively.

Lets assume of the 10 tests, Jerry scored;
Case-1: 80 in 6 tests, and 60 in 4 tests, so his total score will be = 80*6 + 60*4 = 480 + 240 = 720. Hence his average score will be 720/10 = 72

Case-2: 80 in 4 tests, and 60 in 6 tests, so his total score will be = 80*4 + 60*6 = 320 + 360 = 680. Hence his average score will be 680/10 = 68

So, there can be 10 such cases, and in each case there will be a different average score.
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Jerry took a total of 10 tests, some in June and some in July last yea [#permalink]
20 Jan 2021, 14:38
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