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Jijil, Savy, and Tes share an apartment that has a monthly rent of $15

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Jijil, Savy, and Tes share an apartment that has a monthly rent of $15  [#permalink]

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New post 20 Sep 2018, 10:50
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Difficulty:

  15% (low)

Question Stats:

87% (00:54) correct 13% (00:31) wrong based on 23 sessions

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Jijil, Savy, and Tes share an apartment that has a monthly rent of $150. If Savy pays twice as much as Jijil and Tes pays $30 more than Savy does, how much does Jijil pay each month?

1. $ 22

2. $ 24

3. $ 26

4. $ 28

5. $ 30

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Re: Jijil, Savy, and Tes share an apartment that has a monthly rent of $15  [#permalink]

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New post 20 Sep 2018, 11:22
AkshdeepS wrote:
Jijil, Savy, and Tes share an apartment that has a monthly rent of $150. If Savy pays twice as much as Jijil and Tes pays $30 more than Savy does, how much does Jijil pay each month?

1. $ 22

2. $ 24

3. $ 26

4. $ 28

5. $ 30


\(J : S : T = x : 2x : ( 2x + 30)\)

So, \(x + 2x + 2x + 30 = 150\)

Or, \(5x = 120\)

Or, \(x = 24\), So Jill pays $ 24, Answer must be (2)
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Re: Jijil, Savy, and Tes share an apartment that has a monthly rent of $15  [#permalink]

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New post 20 Sep 2018, 11:24
J+S+T=150
S/2+S+S+30=150
5S=240
S=48 > J=S/2=24 Answer 2. is correct
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Jijil, Savy, and Tes share an apartment that has a monthly rent of $15  [#permalink]

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New post 20 Sep 2018, 22:07
J+S+T = 150

J = x
S = 2x
T = 30+2x

So, x+2x+30+2x=150

=> 5x+30 = 150
=>5x=120
=>x=120/5
=>x=24

Hence the answer is (2)

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Re: Jijil, Savy, and Tes share an apartment that has a monthly rent of $15  [#permalink]

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New post 20 Sep 2018, 22:34
AkshdeepS wrote:
Jijil, Savy, and Tes share an apartment that has a monthly rent of $150. If Savy pays twice as much as Jijil and Tes pays $30 more than Savy does, how much does Jijil pay each month?

1. $ 22

2. $ 24

3. $ 26

4. $ 28

5. $ 30


OA: B

Let the Jijil's rent share be \($ x\).

Rent share of Savy = \(2*$ x\)

Rent share of Tes = \(2*$ x+$ 30\)

Jijil's rent + Savy's rent + Tes's rent = \($ 150\)

\($ x + 2*$ x +2*$ x+$ 30 = $ 150\)

\(5*$ x + $ 30 = $ 150\)

\(5*$ x = $ 150 - $ 30 =$ 120\)

Jijil's rent \(=$ x =\frac{$ 120}{5} = $ 24\)
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Re: Jijil, Savy, and Tes share an apartment that has a monthly rent of $15 &nbs [#permalink] 20 Sep 2018, 22:34
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