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Math Expert
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Re: M03-17 [#permalink]
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msk0657 wrote:
Bunuel wrote:
Official Solution:


(1) \(2^k=1\). Since any nonzero number to the power of 0 is 1 then \(k=0\). Sufficient.

(2) \(1^k=1\). This equation holds true for any value of \(k\). Not sufficient.


Answer: A



Hi Bunuel,

Can you please explain point number 2. (This equation holds true for any value of \(k\). Not sufficient.)

A. When 2 power K = 2 power 0 = 1...I thought this is fine.. sufficient.

B. When 1 power K = 1 power 0 = 1....thought even this is sufficient. Then I chose D.


Hi,
the reason mentioned by you is the very reason that statement II is NOT suff...
you take any value of K,

(2) \(1^k=1\).
K=1....\(1^1=1\)....
K=2....\(1^2=1\)....
so k can take any value 1,2,3,4..
so insuff
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Re: M03-17 [#permalink]
Expert Reply
I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Re M03-17 [#permalink]
I think this is a high-quality question and I agree with explanation.
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Re M03-17 [#permalink]
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