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(1) The greatest integer is 4. Since 4 is the greatest integer out of 6 consecutive integers, then all 6 integers can be found and thus the product calculated. Sufficient.
Just to illustrate: 6 consecutive integers would be {-1, 0, 1, 2, 3, 4}. Since there is a zero among them, the product will also be zero.
(2) The sequence has both positive and negative integers. Since a sequence of consecutive integers has both positive and negative numbers in it, then it must also contain zero, so the product of the terms of such sequence will also be zero. Sufficient.
From 2 statement : The sequence has both positive and negative integers I knew the condition is Consecutive Integer, I considerd 2 cases Case 1: Odd consecutive integer (-3,-1,1,3,5,7) In this case the Product is Negative Integer Case 2: Even consecutive Integers (-4,-2,0,2,4,6) In this case product is zero So I have chosen A
Pls help me in any analysis.
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I welcome analysis on my posts and kudo +1 if helpful. It helps me to improve my craft.Thank you
From 2 statement : The sequence has both positive and negative integers I knew the condition is Consecutive Integer, I considerd 2 cases Case 1: Odd consecutive integer (-3,-1,1,3,5,7) In this case the Product is Negative Integer Case 2: Even consecutive Integers (-4,-2,0,2,4,6) In this case product is zero So I have chosen A
Pls help me in any analysis.
Hi, The statement talks of CONSECUTIVE integers, and it will always mean terms having difference of 1.. So -1,0,1,2...
Only if it is given CONSECUTIVE odd integers, you will take -1,1,3... And if CONSECUTIVE even integers, -2,0,2,4...
Here you will have,-2,-1,0,1,2... or -4,-3,-2,-1,0,1.. Each time product will be 0 Hence sufficient
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I think this is a high-quality question. This is an awesome question. I seriously faltered on the second statement. Presence of mind is important within the context what are we trying to find
I thought the Factorial of 0! is 1, therefore -1*0 = 0! = 1, so the numbers can be {-2,-1,0,-1,-2,-3} and any set such as {-1,0,-1,-2,-3, -4} So both will have different product, I think I have misunderstanding with regard to "0!" can someone please explain me this concept.
I thought the Factorial of 0! is 1, therefore -1*0 = 0! = 1, so the numbers can be {-2,-1,0,-1,-2,-3} and any set such as {-1,0,-1,-2,-3, -4} So both will have different product, I think I have misunderstanding with regard to "0!" can someone please explain me this concept.
1. Yes, 0! = 1 but it's highly unlikely that you'll need this for the GMAT. 2. Factorial of integer n, n!, is defined for non-negative n. 3. -1*0 = 0, and it is not the same as 0!. 4. 0*1 = 0 and it is not the same as 0!. 5. Anything*0 = 0.
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I'm sorry but I do not understand your point "2. Factorial of integer n, n!, is defined for non-negative n." ?
Also, 7!/10! can be written as 7!/7! * 8*9*10, therefore cant we write -1*0*1*2*3*4 as 0!*1*2*3*4, thus giving us the answer "24" and not 0.
Factorial of a positive integer \(n\), denoted by \(n!\), is the product of all positive integers less than or equal to n. For instance \(5!=1*2*3*4*5\).
Note: factorial of negative numbers is undefined. _________________
Thanks for posting this question. It highlights the value of visualizing/seeing the sequence on the pad/paper. A quality question that could trip you to answer A if you don't visualize and put the pen to the pad.
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52% (00:27) correct 
