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16 Sep 2014, 00:33
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E
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Difficulty:
15%
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Question Stats:
85% (02:03) correct
15%
(02:33)
wrong
based on 647
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In a Commonwealth condominium complex, there are \(k\) apartments. Out of these, \(n\) apartments are currently rented, each at a rate of \(s\) dollars a month, yielding a total monthly revenue of \(p\) dollars. If the management plans to reduce the rent by \(m\)% to achieve 100% occupancy, what will be the total monthly revenue?
A. \((k-n)\frac{p}{m}\)
B. \(k*\frac{s}{p}*\frac{m}{100}\)
C. \(k+\frac{s}{p} + km\)
D. \(\frac{sp}{100m}\)
E. \(ks(1 - \frac{m}{100})\)
A. \((k-n)\frac{p}{m}\)
B. \(k*\frac{s}{p}*\frac{m}{100}\)
C. \(k+\frac{s}{p} + km\)
D. \(\frac{sp}{100m}\)
E. \(ks(1 - \frac{m}{100})\)
16 Sep 2014, 00:33
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Official Solution:
In a Commonwealth condominium complex, there are \(k\) apartments. Out of these, \(n\) apartments are currently rented, each at a rate of \(s\) dollars a month, yielding a total monthly revenue of \(p\) dollars. If the management plans to reduce the rent by \(m\)% to achieve 100% occupancy, what will be the total monthly revenue?
A. \((k-n)\frac{p}{m}\)
B. \(k*\frac{s}{p}*\frac{m}{100}\)
C. \(k+\frac{s}{p} + km\)
D. \(\frac{sp}{100m}\)
E. \(ks(1 - \frac{m}{100})\)
Revenue is calculated as Occupancy multiplied by Rent. Given that the new occupancy is \(k\) (meaning all \(k\) apartments are rented at 100% occupancy) and the adjusted rent is \(s(1-\frac{m}{100})\) (reflecting a decrease of \(m\%\) from the original rent of \(s\) dollars), the Revenue can be expressed as \(ks(1-\frac{m}{100})\).
Answer: E
In a Commonwealth condominium complex, there are \(k\) apartments. Out of these, \(n\) apartments are currently rented, each at a rate of \(s\) dollars a month, yielding a total monthly revenue of \(p\) dollars. If the management plans to reduce the rent by \(m\)% to achieve 100% occupancy, what will be the total monthly revenue?
A. \((k-n)\frac{p}{m}\)
B. \(k*\frac{s}{p}*\frac{m}{100}\)
C. \(k+\frac{s}{p} + km\)
D. \(\frac{sp}{100m}\)
E. \(ks(1 - \frac{m}{100})\)
Revenue is calculated as Occupancy multiplied by Rent. Given that the new occupancy is \(k\) (meaning all \(k\) apartments are rented at 100% occupancy) and the adjusted rent is \(s(1-\frac{m}{100})\) (reflecting a decrease of \(m\%\) from the original rent of \(s\) dollars), the Revenue can be expressed as \(ks(1-\frac{m}{100})\).
Answer: E
saurabh9gupta
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15 Aug 2019, 01:19
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Bunuel
A Commonwealth condominium complex has \(k\) apartments, \(n\) of which are rented at \(s\) dollars a month, providing a total monthly revenue of \(p\) dollars. If the management is planning to decrease the rent by \(m\)%, to increase the occupancy to 100%, how much total revenue will it collect?
A. \((k-n)\frac{p}{m}\)
B. \(k*\frac{s}{p}*\frac{m}{100}\)
C. \(k+\frac{s}{p} + km\)
D. \(\frac{sp}{100m}\)
E. \(ks(1 - \frac{m}{100})\)
A. \((k-n)\frac{p}{m}\)
B. \(k*\frac{s}{p}*\frac{m}{100}\)
C. \(k+\frac{s}{p} + km\)
D. \(\frac{sp}{100m}\)
E. \(ks(1 - \frac{m}{100})\)
Nice question:
Another method
Assume -
Total apt (k) 20
Total rented (n) = 10
Monthly rent (s) = 10
Total Rev (p) = 10 * 10 = 100
now
M=50%
so total revenue = 20 * 5 = 100
substitute and only E will stand.
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