NandishSS
HI
GMATGuruNY,
AndrewN ,
GMATCoachBen ,
BunuelI'm not clear about Statement (2)The width of the 18''-screen is 20% greater than that of the 15''-screen. We are not aware of the length?
So I marked as A
Hello,
NandishSS. I see that
GMATGuruNY has already supplied a fine response to your query. I took a less rigorous approach but arrived at the same conclusion within a minute. I started with the idea that the two rectangular screens
might be similar figures, if only I had enough information to prove it one way or the other. Now, the given diagonals fit a proportion:
\(\frac{18}{15}=\frac{6}{5}\)
The decimal equivalent is 1.2. If we knew that either of the other sides of the larger rectangle were 1.2 times greater than its corresponding side on the smaller rectangle, we would be able to deduce that the third side also had to fit the same proportion, using the Pythagorean theorem. Consider:
Smaller right triangle:
\(a^2+b^2=c^2\)
Larger right triangle:
\((1.2a)^2+(1.2b)^2=(1.2c)^2\)
Notice that statement (2) gives us just what we want. If we let
w represent the width of the 15" screen, then 1.2
w would represent the width of the 18" screen. That is as far as I went with it, to be honest. I knew I had the information I needed, so I picked (D).
I hope that helps. Thank you for thinking to tag me.
- Andrew