GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 05 Dec 2019, 17:34

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

M23-26

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 59561

Show Tags

16 Sep 2014, 01:19
00:00

Difficulty:

35% (medium)

Question Stats:

65% (00:54) correct 35% (01:02) wrong based on 113 sessions

HideShow timer Statistics

If $$|x| \lt 4$$, what is the value of $$x$$ ?

(1) $$x$$ is an integer divisible by 3

(2) $$x$$ is an integer divisible by 2
Math Expert
Joined: 02 Sep 2009
Posts: 59561

Show Tags

16 Sep 2014, 01:19
1
2
Official Solution:

Statement (1) by itself is insufficient. Consider $$x = 3$$ and $$x = -3$$.

Statement (1) by itself is insufficient. Consider $$x = 2$$ and $$x = -2$$.

Statements (1) and (2) combined are sufficient. $$x = 0$$.

Current Student
Joined: 05 Dec 2015
Posts: 11

Show Tags

07 Aug 2016, 15:14
how do statements 1 and 2 lead us to zero? How about 6 and -6 as they are both divisible by 2 and 3. so i thought both statements combined are not sufficient.
Math Expert
Joined: 02 Sep 2009
Posts: 59561

Show Tags

08 Aug 2016, 01:05
ehiszele wrote:
how do statements 1 and 2 lead us to zero? How about 6 and -6 as they are both divisible by 2 and 3. so i thought both statements combined are not sufficient.

It's given in the stem that |x| < 4, which means that -4 < x < 4.
Intern
Joined: 07 Feb 2016
Posts: 20
GMAT 1: 650 Q47 V34
GMAT 2: 710 Q48 V39

Show Tags

17 Apr 2017, 02:02
NaijaBoy234 wrote:
how do statements 1 and 2 lead us to zero? How about 6 and -6 as they are both divisible by 2 and 3. so i thought both statements combined are not sufficient.

$$\frac{0}{3}=0$$

$$\frac{0}{2}=0$$

and $$0$$ is an integer as well.
Manager
Joined: 17 May 2017
Posts: 119
Schools: ESSEC '20
GPA: 3

Show Tags

06 Oct 2017, 12:33
1 is also divisible by 6 isn't it?
Math Expert
Joined: 02 Sep 2009
Posts: 59561

Show Tags

07 Oct 2017, 02:00
haardiksharma wrote:
1 is also divisible by 6 isn't it?

Integer x is divisible by integer y means that x/y = integer, so x when divided by y leaves no remainder. 1/6 is not an integer, 1 divided by 6 gives the remaimder of 1, so NO 1 is NOT divisible by 6.
Intern
Joined: 06 Jan 2018
Posts: 21
GMAT 1: 790 Q50 V51

Show Tags

03 Feb 2018, 00:39
From (1) we know that x could be -3, 0 or 3 (all numbers between -4 and 4 that are divisible by 3). Not sufficient.

From (2) we know that x could be -2, 0 or 2. Not sufficient.

From (1) and (2) combined, the only number which appears in both sets is 0, so this is sufficient.

0 is divisible by everything. The trap would be forgetting to include 0 in the original lists.
Intern
Joined: 26 Sep 2018
Posts: 3

Show Tags

28 Aug 2019, 13:34
This is a very nicely crafted and GMAT-like math. Kudos to the maker.
Re: M23-26   [#permalink] 28 Aug 2019, 13:34
Display posts from previous: Sort by

M23-26

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

Moderators: chetan2u, Bunuel

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne