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M23-26

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M23-26  [#permalink]

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New post 16 Sep 2014, 01:19
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  35% (medium)

Question Stats:

67% (00:54) correct 33% (01:01) wrong based on 110 sessions

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Re M23-26  [#permalink]

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New post 16 Sep 2014, 01:19
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Re: M23-26  [#permalink]

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New post 07 Aug 2016, 15:14
how do statements 1 and 2 lead us to zero? How about 6 and -6 as they are both divisible by 2 and 3. so i thought both statements combined are not sufficient.
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New post 08 Aug 2016, 01:05
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Re: M23-26  [#permalink]

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New post 17 Apr 2017, 02:02
NaijaBoy234 wrote:
how do statements 1 and 2 lead us to zero? How about 6 and -6 as they are both divisible by 2 and 3. so i thought both statements combined are not sufficient.


\(\frac{0}{3}=0\)

\(\frac{0}{2}=0\)

and \(0\) is an integer as well.
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New post 06 Oct 2017, 12:33
1 is also divisible by 6 isn't it?
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New post 07 Oct 2017, 02:00
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New post 03 Feb 2018, 00:39
From (1) we know that x could be -3, 0 or 3 (all numbers between -4 and 4 that are divisible by 3). Not sufficient.

From (2) we know that x could be -2, 0 or 2. Not sufficient.

From (1) and (2) combined, the only number which appears in both sets is 0, so this is sufficient.

0 is divisible by everything. The trap would be forgetting to include 0 in the original lists.
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Re: M23-26  [#permalink]

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New post 28 Aug 2019, 13:34
This is a very nicely crafted and GMAT-like math. Kudos to the maker.
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Re: M23-26   [#permalink] 28 Aug 2019, 13:34
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