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Re: Mark can paint twice as fast as Joe. If Mark starts to paint at one en [#permalink]
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classic application of ratios,,,

given ratio of rate is 2:1,, hence distance covered will be 2:1

from mark's end distance covered will 2/3 of the total distance

ans B
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Re: Mark can paint twice as fast as Joe. If Mark starts to paint at one en [#permalink]
Through POE you can eliminate C,D,E..Because by time Joe did his 1/4 of a mile, mark would have completed 1/2 mille, meaning that at minimum Mark is 1/2 a mile away from his starting point;however, they together still have to complete 1/4 more of the mile which will push Mark even further from the 1/2 mile mark. So A, C, D, & E can be eliminated.
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Re: Mark can paint twice as fast as Joe. If Mark starts to paint at one en [#permalink]
BrentGMATPrepNow wrote:
Bunuel wrote:
Mark can paint twice as fast as Joe. If Mark starts to paint at one end of a mile-long wall and Joe starts to paint at the other end of the wall, how far away from Mark's end of the wall will they meet?

A. 3/4 mile
B. 2/3 mile
C. 1/2 mile
D. 1/3 mile
E. 1/4 mile


Mark can paint twice as fast as Joe.
For every 1 foot of fence that Joe paints, Mark paints 2 feet.
So, out of every 3 feet of fence that gets painted, Mark paints 2 feet
In other words, Mark does 2/3 of the work.

So, if their combined efforts yields 1 mile of painting, then we know that Mark completed 2/3 of the job.
So, Mark painted 2/3 miles of fence.

Answer:

Cheers,
Brent


Hi Brent BrentGMATPrepNow, very great shortcut.
Just in case not thought of it at exam, could you show how to solve this using work rate formula? Thanks Brent
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Mark can paint twice as fast as Joe. If Mark starts to paint at one en [#permalink]
Visualize

30 seconds via visualizing

<-------------|-------|------->
                Mark   Joe
                 1/2    1/4

The answer is between 1/2 and 1/4, answer B looked like the right position
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Mark can paint twice as fast as Joe. If Mark starts to paint at one en [#permalink]
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