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Mark can paint twice as fast as Joe. If Mark starts to paint at one en

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Mark can paint twice as fast as Joe. If Mark starts to paint at one en  [#permalink]

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New post 28 Apr 2017, 03:25
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Mark can paint twice as fast as Joe. If Mark starts to paint at one end of a mile-long wall and Joe starts to paint at the other end of the wall, how far away from Mark's end of the wall will they meet?

A. 3/4 mile
B. 2/3 mile
C. 1/2 mile
D. 1/3 mile
E. 1/4 mile

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Re: Mark can paint twice as fast as Joe. If Mark starts to paint at one en  [#permalink]

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New post 28 Apr 2017, 06:14
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Bunuel wrote:
Mark can paint twice as fast as Joe. If Mark starts to paint at one end of a mile-long wall and Joe starts to paint at the other end of the wall, how far away from Mark's end of the wall will they meet?

A. 3/4 mile
B. 2/3 mile
C. 1/2 mile
D. 1/3 mile
E. 1/4 mile


Mark can paint twice as fast as Joe.
For every 1 foot of fence that Joe paints, Mark paints 2 feet.
So, out of every 3 feet of fence that gets painted, Mark paints 2 feet
In other words, Mark does 2/3 of the work.

So, if their combined efforts yields 1 mile of painting, then we know that Mark completed 2/3 of the job.
So, Mark painted 2/3 miles of fence.

Answer:

Cheers,
Brent
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Re: Mark can paint twice as fast as Joe. If Mark starts to paint at one en  [#permalink]

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New post 02 May 2017, 04:36
classic application of ratios,,,

given ratio of rate is 2:1,, hence distance covered will be 2:1

from mark's end distance covered will 2/3 of the total distance

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Re: Mark can paint twice as fast as Joe. If Mark starts to paint at one en  [#permalink]

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New post 02 May 2017, 16:53
2
Bunuel wrote:
Mark can paint twice as fast as Joe. If Mark starts to paint at one end of a mile-long wall and Joe starts to paint at the other end of the wall, how far away from Mark's end of the wall will they meet?

A. 3/4 mile
B. 2/3 mile
C. 1/2 mile
D. 1/3 mile
E. 1/4 mile


Since Mark can paint twice as fast as Joe, he will paint twice as much of the wall (length-wise) as Joe will. If we let x = the length of wall Joe paints, then 2x = the length of wall Mark paints. Therefore:

2x + x = 1

3x = 1

x = 1/3

Thus, Mark paints 2/3 of a mile of the wall, i.e., he is 2/3 of a mile from his end of the wall when he meets Joe.

Answer: B
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Re: Mark can paint twice as fast as Joe. If Mark starts to paint at one en  [#permalink]

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New post 19 Aug 2018, 09:36
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Re: Mark can paint twice as fast as Joe. If Mark starts to paint at one en &nbs [#permalink] 19 Aug 2018, 09:36
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