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Mike, Scott, Jim, Kate, and Pete each have a different number of assig 10 Dec 2019, 01:43
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25% (medium)

Question Stats:

75% (01:59) correct 25% (02:12) wrong based on 179 sessions

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Mike, Scott, Jim, Kate, and Pete each have a different number of assignments this month. Pete has fewer assignments than Kate, Kate has more assignments than Mike, Mike has more assignments than Jim, and Jim has more assignments than Scott. Which of the following could be the person who has the median number of assignments this month for the five people listed?

I. Mike
II. Jim
III. Pete

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III


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E
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GMAT Focus 1: 735 Q90 V89 DI81
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Mike, Scott, Jim, Kate, and Pete each have a different number of assig 10 Dec 2019, 02:00
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Bunuel
Mike, Scott, Jim, Kate, and Pete each have a different number of assignments this month. Pete has fewer assignments than Kate, Kate has more assignments than Mike, Mike has more assignments than Jim, and Jim has more assignments than Scott. Which of the following could be the person who has the median number of assignments this month for the five people listed?

I. Mike
II. Jim
III. Pete

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III


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Let us work on the inequalities
P<K, K>M, M>J, J>S...
So K>M>J>S
Now P can be anywhere after K as we are looking for COULD

I. M
K>P>M>J>S
II J
K>M>J>S>P
III. P
K>M>P>J>S

All three possible...E
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Mike, Scott, Jim, Kate, and Pete each have a different number of assig 11 Dec 2019, 07:55
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Bunuel
Mike, Scott, Jim, Kate, and Pete each have a different number of assignments this month. Pete has fewer assignments than Kate, Kate has more assignments than Mike, Mike has more assignments than Jim, and Jim has more assignments than Scott. Which of the following could be the person who has the median number of assignments this month for the five people listed?

I. Mike
II. Jim
III. Pete

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III
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p<k, k>m, m>j, j>s, k>m>j>s, k>p
k>[p]>m>j>s: median = m
k>m>[p]>j>s: median = p
k>m>j>[p]>s: median = j

Ans (E)
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Mike, Scott, Jim, Kate, and Pete each have a different number of assig 12 Dec 2019, 19:51
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Bunuel
Mike, Scott, Jim, Kate, and Pete each have a different number of assignments this month. Pete has fewer assignments than Kate, Kate has more assignments than Mike, Mike has more assignments than Jim, and Jim has more assignments than Scott. Which of the following could be the person who has the median number of assignments this month for the five people listed?

I. Mike
II. Jim
III. Pete

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III


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We have:

K > P

K > M

M > J

J > S

Using the inequalities above, we can determine the number of assignments (except for Pete) is ordered as:

K > M > J > S

If P > M, then the median is M.

If M > P > J, then the median is P.

If J > P, then the median is J.

Thus, we see that the person with the median number of assignments could be Mike, Pete or Jim.

Answer: E
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Mike, Scott, Jim, Kate, and Pete each have a different number of assig 16 Dec 2019, 03:11
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Assuming Mike = M, Jim = J, Kate = K, and Pete = P

Given, K>P; K>M; M>J; J>S

From the above, we can say K>P and K>M>J>S

Listing the possibilities now (in increasing order) to calculate the median:

K-M-J-S-P (Median is J)
K-P-M-J-S (Median is M)
K-M-P-J-S (Median is P)

Hence, we have all three possibilities i.e. J,M and P

Answer is E
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Mike, Scott, Jim, Kate, and Pete each have a different number of assig 19 Sep 2024, 13:34
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