Last visit was: 20 Jul 2024, 00:35 It is currently 20 Jul 2024, 00:35
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Math Expert
Joined: 02 Sep 2009
Posts: 94421
Own Kudos [?]: 642429 [0]
Given Kudos: 86332
Send PM
RC & DI Moderator
Joined: 02 Aug 2009
Status:Math and DI Expert
Posts: 11476
Own Kudos [?]: 34456 [0]
Given Kudos: 322
Send PM
SVP
SVP
Joined: 24 Nov 2016
Posts: 1712
Own Kudos [?]: 1360 [0]
Given Kudos: 607
Location: United States
Send PM
Target Test Prep Representative
Joined: 14 Oct 2015
Status:Founder & CEO
Affiliations: Target Test Prep
Posts: 19175
Own Kudos [?]: 22679 [0]
Given Kudos: 286
Location: United States (CA)
Send PM
Re: Mike, Scott, Jim, Kate, and Pete each have a different number of assig [#permalink]
Expert Reply
Bunuel wrote:
Mike, Scott, Jim, Kate, and Pete each have a different number of assignments this month. Pete has fewer assignments than Kate, Kate has more assignments than Mike, Mike has more assignments than Jim, and Jim has more assignments than Scott. Which of the following could be the person who has the median number of assignments this month for the five people listed?

I. Mike
II. Jim
III. Pete

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III


Are You Up For the Challenge: 700 Level Questions


We have:

K > P

K > M

M > J

J > S

Using the inequalities above, we can determine the number of assignments (except for Pete) is ordered as:

K > M > J > S

If P > M, then the median is M.

If M > P > J, then the median is P.

If J > P, then the median is J.

Thus, we see that the person with the median number of assignments could be Mike, Pete or Jim.

Answer: E
Intern
Intern
Joined: 29 Jan 2018
Posts: 2
Own Kudos [?]: 5 [0]
Given Kudos: 12
Location: India
WE:Social Work (Consulting)
Send PM
Re: Mike, Scott, Jim, Kate, and Pete each have a different number of assig [#permalink]
Assuming Mike = M, Jim = J, Kate = K, and Pete = P

Given, K>P; K>M; M>J; J>S

From the above, we can say K>P and K>M>J>S

Listing the possibilities now (in increasing order) to calculate the median:

K-M-J-S-P (Median is J)
K-P-M-J-S (Median is M)
K-M-P-J-S (Median is P)

Hence, we have all three possibilities i.e. J,M and P

Answer is E
GMAT Club Bot
Re: Mike, Scott, Jim, Kate, and Pete each have a different number of assig [#permalink]
Moderator:
Math Expert
94421 posts