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No. Properties

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Senior Manager
Joined: 05 Oct 2008
Posts: 267

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04 Feb 2009, 09:02
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If -2x > 3y, is x negative

1. y > 0
2. 2x + 5y - 20 =0
SVP
Joined: 07 Nov 2007
Posts: 1789
Location: New York

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04 Feb 2009, 09:28
study wrote:
If -2x > 3y, is x negative

1. y > 0
2. 2x + 5y - 20 =0

1) y>0 clearly x<0
sufficient

2)
-2x > 3y

3y+2x<0

2x + 5y - 20 =0 --> 20-2y= 2x+3y <0

20-2y <0

2y>2o y +ve

so X is -ve

sufficient

D
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Intern
Joined: 12 Dec 2008
Posts: 1

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04 Feb 2009, 09:29
If -2x > 3y, is x negative

1. y > 0
2. 2x + 5y - 20 =0

Given -2x > 3y

Or x<-3/2y Question Rephrase: Is x<0? Now x<0 if y>0.So the question asks Is y>0?

From A: y>0; Which is true. Hence sufficient.

From B: x=5/2(4-y). Now if 0<y<4 then x>0.But if y>4 then x negative.We know nothing bout Y.Hence insufficient.

Thus ans A
SVP
Joined: 17 Jun 2008
Posts: 1529

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04 Feb 2009, 09:31
D.

Stmt1 is sufficient.

From stmt2: (2x + 3y) + 2y - 20 = 0
Now, since 2x+3y < 0, 2y - 20 > 0 or, y > 0 and hence x < 0. Sufficient.
SVP
Joined: 29 Aug 2007
Posts: 2467

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04 Feb 2009, 10:16
study wrote:
If -2x > 3y, is x negative

1. y > 0
2. 2x + 5y - 20 =0

Agree with D.

Given that:
-2x > 3y
0 > (2x + 3y)

Statement 1: self explanatory.
Statement 2: 2x + 5y - 20 = 0
2x + 5y = 20
2x + 3Y = 20 - 2Y

Since (2x + 3y) is -ve, (20 - 2Y) also has to be -ve and that is possible only when y is greater than 10. Suff.
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Re: No. Properties   [#permalink] 04 Feb 2009, 10:16
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No. Properties

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