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Of 120 hotel rooms rented one night, some were suits rented for $115

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Of 120 hotel rooms rented one night, some were suits rented for $115  [#permalink]

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New post 17 Apr 2017, 09:28
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Difficulty:

  25% (medium)

Question Stats:

79% (02:23) correct 21% (02:36) wrong based on 187 sessions

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Of 120 hotel rooms rented one night, some were suits rented for $115 each and the rest were double rooms rented for $85 each. If the total revenue from the room rentals ffor this night was $10890, how many suits were rented?

A) 23
B) 35
C) 54
D) 94
E) 99

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Re: Of 120 hotel rooms rented one night, some were suits rented for $115  [#permalink]

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New post 17 Apr 2017, 10:20
4
Let x be suites and y be double rooms

X+y=120
Y=120-x
115x+85y=10890
115x+85(120-x)=10890
30x=690
X=23

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Re: Of 120 hotel rooms rented one night, some were suits rented for $115  [#permalink]

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New post 17 Apr 2017, 10:20
Vanmotan wrote:
Of 120 hotel rooms rented one night, some were suits rented for $115 each and the rest were double rooms rented for $85 each. If the total revenue from the room rentals ffor this night was $10890, how many suits were rented?

A) 23
B) 35
C) 54
D) 94
E) 99



Let the number of suits rented = x
Then number of double rooms rented = 120-x

Revenue from suits = 115*x
Revenue from double rooms = 85*(120-x)
Total revenue = 115x + 85(120-x) = 10890
=> 115x + 10200 - 85x = 10890
=> 30x = 690
=> x = 23

Thus, 23 suits were rented.
A) is the answer.


If you like my post please reward with kudos. :-D
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GMAT 2: 730 Q50 V38
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Re: Of 120 hotel rooms rented one night, some were suits rented for $115  [#permalink]

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New post 17 Apr 2017, 10:46
tiklimumita wrote:
Vanmotan wrote:
Of 120 hotel rooms rented one night, some were suits rented for $115 each and the rest were double rooms rented for $85 each. If the total revenue from the room rentals ffor this night was $10890, how many suits were rented?

A) 23
B) 35
C) 54
D) 94
E) 99



Let the number of suits rented = x
Then number of double rooms rented = 120-x

Revenue from suits = 115*x
Revenue from double rooms = 85*(120-x)
Total revenue = 115x + 85(120-x) = 10890
=> 115x + 10200 - 85x = 10890
=> 30x = 690
=> x = 23

Thus, 23 suits were rented.
A) is the answer.


If you like my post please reward with kudos. :-D


I used the similar approach, but divided everything by 5 at the beginning:

1) S+D=120

2) 23*S+17*D=2178

Substitute D for S:
23*S+2040-17*S=2178

6*S=138

S=23
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Re: Of 120 hotel rooms rented one night, some were suits rented for $115  [#permalink]

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New post 27 Aug 2018, 03:02
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Re: Of 120 hotel rooms rented one night, some were suits rented for $115   [#permalink] 27 Aug 2018, 03:02
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