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Re: On 1st January of a certain year, Jones invested a total of $10000 u [#permalink]
commodork71 wrote:
Using statement #1 and the prompt, we can write 2 equations for the 2 unknowns: X(1.05)-300= Y(1.03) and X+Y=10,000. As a rule, you need x amount of distinct equations to solve for x amount of variables. Thus, without solving the equations, you know there is sufficient information.

Using statement #2 and the prompt you can do the same thing: X+Y=10,000 and X-Y=7,000. Again, you would only need to recognize that you have 2 equations for 2 unknowns to see that it's sufficient.

Note that this rule only applies for distinct equations. What I mean by that is that both offer information that is not contained in the other. For example, if the equations you were given were X+Y=10,000 and 2(X+Y)=20,000, you really only have one useful equation.

So here the answer is that either are sufficient on their own.



With the second statement, you are able to determine that one investment is for x value, and the second one for y value, but then you do not know which is which... am i correct? Therefore statement 2 would be insufficient.
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Re: On 1st January of a certain year, Jones invested a total of $10000 u [#permalink]
With the second statement, you are able to determine that one investment is for x value, and the second one for y value, but then you do not know which is which... am i correct? Therefore statement 2 would be insufficient.[/quote]

I think you're right! My apologies.
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Re: On 1st January of a certain year, Jones invested a total of $10000 u [#permalink]
commodork71 wrote:
Using statement #1 and the prompt, we can write 2 equations for the 2 unknowns: X(1.05)-300= Y(1.03) and X+Y=10,000. As a rule, you need x amount of distinct equations to solve for x amount of variables. Thus, without solving the equations, you know there is sufficient information.

Using statement #2 and the prompt you can do the same thing: X+Y=10,000 and X-Y=7,000. Again, you would only need to recognize that you have 2 equations for 2 unknowns to see that it's sufficient.

Note that this rule only applies for distinct equations. What I mean by that is that both offer information that is not contained in the other. For example, if the equations you were given were X+Y=10,000 and 2(X+Y)=20,000, you really only have one useful equation.

So here the answer is that either are sufficient on their own.

­From statement 1, we only know the difference which means, either X(1.05)-300= Y(1.03) OR X(1.05)+ 300= Y(1.03) which will give you two different answers. Isn't it ?
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Re: On 1st January of a certain year, Jones invested a total of $10000 u [#permalink]

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