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Math Revolution GMAT Instructor
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Math Revolution GMAT Instructor
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Re: One cup of sugar water was poured out of 300 g of 8% sugar water and t [#permalink]
Expert Reply
=>
Suppose \(x\) is the weight of sugar water poured out.

Then \((\frac{8}{100})(300-x) + (\frac{2}{100})(400-300) = (\frac{6}{100})(400)\) or \(8(300-x) + 200 = 2400.\)

So, \(8x = 200\) and \(x = 25.\)

Therefore, B is the answer.
Answer: B
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Re: One cup of sugar water was poured out of 300 g of 8% sugar water and t [#permalink]
GMATGuruNY
please see highlighted part

GMATGuruNY wrote:
MathRevolution wrote:
[GMAT math practice question]

One cup of sugar water was poured out of 300 g of 8% sugar water and then the same amount of pure water was poured into the solution. After that 2% sugar water was added, resulting in 400 g of 6% sugar water. What weight of sugar water was initially poured out?

A. 20 g
B. 25 g
C. 30 g
D. 35 g
E. 40 g


Resulting amount of sugar = 6% of 400 grams = 24 grams.

Since the added sugar water increases the total volume from 300 grams to 400 grams, the amount of added sugar water = 400-300 = 100 grams
Since the added sugar water is 2% sugar, the weight of the added sugar = 2% of 100 = 2 grams.
Implication:
Before the 2% sugar water is added, the amount of sugar in the container = 24-2 = 22 grams.

Original amount of sugar in the container = 8% of 300 grams = 24 grams.
Since the removal process decreases the original amount of sugar from 24 grams to 22 grams, the amount of sugar removed = 24-2 = 2 grams.
Since the original solution is 8% sugar, these 2 grams must constitute 8% of the removed sugar water:
\(2 = \frac{8}{100}x\)
\(x = \frac{100}{8} = 25\)
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Re: One cup of sugar water was poured out of 300 g of 8% sugar water and t [#permalink]
Expert Reply
Archit3110 wrote:
GMATGuruNY
please see highlighted part


I've corrected the typo. Thanks for calling it to my attention.
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Re: One cup of sugar water was poured out of 300 g of 8% sugar water and t [#permalink]
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