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Re: beat this: contradicting statements [#permalink]
yeh Macfauz.

If we incorrectly solve 2nd equation by factoring (x-4)(x-6) , then the 2 statements would contradict..

So I guess, if we find that the statements are contradicting , then we can be sure that we have made a mistake somewhere ..
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Re: beat this: contradicting statements [#permalink]
Sachin9 wrote:
yeh Macfauz.

If we incorrectly solve 2nd equation by factoring (x-4)(x-6) , then the 2 statements would contradict..


Why would we be solving the equation incorrectly? :lol:
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Re: beat this: contradicting statements [#permalink]
Marcab wrote:
Sachin9 wrote:
yeh Macfauz.

If we incorrectly solve 2nd equation by factoring (x-4)(x-6) , then the 2 statements would contradict..


Why would we be solving the equation incorrectly? :lol:

in case you ever do, in the heat of the pressure . then this knowledge will help you know you have gone wrong :D
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Re: beat this: contradicting statements [#permalink]
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Sachin9 wrote:
Marcab wrote:
Sachin9 wrote:
yeh Macfauz.

If we incorrectly solve 2nd equation by factoring (x-4)(x-6) , then the 2 statements would contradict..


Why would we be solving the equation incorrectly? :lol:

in case you ever do, in the heat of the pressure . then this knowledge will help you know you have gone wrong :D


You can not do the factorization incorrectly if you know the concept. The -ve sign before 24 indicates you to choose two factors of 24 and subtract it from each other to make 10. So only (12,2) this pair will satisfy.

As per your factorization (x-4)(x-6) the equation becomes x^2-10x+24(which is not in the question).

So the + or - sign before the last constant term will give u clue whether u need to add or subtract.
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Re: What is the value of x? [#permalink]
agreed mate.. i said if you do commit mistake in the heat of the pressure...
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Re: What is the value of x? [#permalink]
IMO C

Equating both individually we get
1. x = -2 or x = -3. not sufficient
2. x = -2 or x = 12. not sufficient.

thus 1 and 2 together are sufficient and we get X =2
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Re: What is the value of x? [#permalink]
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