Is ad > bc ?

Hi CAMANISHPARMAR

Sometimes plugging-in values is time consuming but we can easily fix numbers and play with others, for example in statement 1

\(\frac{a}{b} > \frac{c}{d}\)

Let a=0, b=1, this will make LHS =0.......So choose any small numbers c= -1 & d=2.......0 > -1.......Answer is Yes

Let a=0, b=1, this will make LHS =0.......So reverse numbers above c= 2 & d=-1.......0 > 2.......Answer is No

Insufficient

Sometimes we tricked to find nice numbers and spend long time to make it fit.

I hope it helps yo maybe in other questions.

Hi Bunuel

Can you explain where am i going wrong, i am getting E.

Is ad>bc?

1) a/b > c/d
if (a,b,c,d) = (2,1,1,1) --> ans is yes
if (a,b,c,d) = (-1,2,-1,4) --> ans is no
insuff.

2) b/d > 0
insuff.

(1) + (2)
if (a,b,c,d) = (2,1,1,1) --> ans is yes
if (a,b,c,d) = (-1,2,-1,4) --> ans is no
insuff.

Hi,

I'm happy to help.

When b =2 & d=4 , then the highlighted past above does not satisfy the condition in statement 1 because -1/2 < -1/4.

If (a,b,c,d) = (-1,2,-1,4), then (a/b = -1/2) < (c/d = -1/4), so this set violates (1).

Hi Buenel,

Why cant A be sufficient for this question:

please find my explanation below and rectify me if I am going wrong any where:

a/b>c/d;
a/b-c/d>0;
(ad-bc)/bd>0;
ad/bd-bc/bd>0;
ad/bd>bc/bd

since,denominator in both the cases are same ,we can say that the numerators decides everything and hence A alone is sufficient.

Regards,
Parth


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Consider the following: \(\frac{2}{(-2)} > \frac{3}{(-2)}\). The denominators are the same but is 2 > 3? No.

The same in \(\frac{ad}{bd}>\frac{bc}{bd}\). ad would be greater than bc if and only bd is positive. In this case we could reduce the inequality by it and get ad > bc. But if bd is negative, then by reducing by it, since it's negative, we should flip the sign and we;d get ad < bc.

Hope it's clear.

The last statement you made (in red) is where you went wrong. All of your math is correct, but you can't make that assumption.

A good guideline is to think through the math you're doing, rather than making assumptions about how the math will work out. (That's how you avoid careless mistakes.)

ad/bd > bc/bd

If you want to 'ignore' the denominators, what you're actually doing is multiplying both sides of the inequality by bd.

However, you can't do that, because you don't know (without using statement 2) whether bd is positive or negative. So, you don't know whether or not to flip the inequality. You wouldn't know whether it would come out to ad > bc, or ad < bc!

Since you don't know, the statement you used is insufficient.

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