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A merchant mixes three varieties of rice costing Rs.20/kg,

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gmatblast
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A merchant mixes three varieties of rice costing Rs.20/kg, [#permalink] New post   17 Jan 2004, 17:57
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A merchant mixes three varieties of rice costing Rs.20/kg, Rs.24/kg and Rs.30/kg and sells the mixture at a profit of 20% at Rs.30 / kg. How many kgs of the second variety will be in the mixture if 2 kgs of the third variety is there in the mixture?

(1) 1 kg (2) 5 kgs (3) 3 kgs (4) 6 kgs

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Re: A merchant mixes three varieties of rice costing Rs.20/kg, [#permalink] New post   17 Jan 2004, 18:02
Hey gmatblast how many kgs of the first variety does he mixes
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Re: A merchant mixes three varieties of rice costing Rs.20/kg, [#permalink] New post   17 Jan 2004, 18:03
rakesh1239 wrote:
Hey gmatblast how many kgs of the first variety does he mixes


That is exactly my problem. It is not given. But there is an answer to this problem. and not sure whether that is correct or not.
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Re: A merchant mixes three varieties of rice costing Rs.20/kg, [#permalink] New post   17 Jan 2004, 18:11
I got the answer has 5kg by assuming the first variety has 1 kg. here it is 1kg----- Rs 20/kg, x kg-------- Rs 24/kg and 2kg----- Rs 30/kg and sells it at 20% profit of y-y @ 30 = Rs 25/kg. so (1+x+2) kgs @ 25 = 20+ 24x + 60 solve for x and we get 5 kgs but I guess the question is wrong
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Re: A merchant mixes three varieties of rice costing Rs.20/kg, [#permalink] New post   26 Jan 2004, 11:27
assuming x is the weight of 2nd type and y of 1st type.

So we have total value as:
y*20+x*24+2*30 ----> 20y+24x+60

Now in the market it was sold at 20% profit at 30Rs/kg, which means

(20y+24x+60)+(20/100)*(20y+24x+60) = 30(x+y+2)

which on resolving will give
x+5y=10

Only option that satisfies the above scenario is 5.
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Re: A merchant mixes three varieties of rice costing Rs.20/kg, [#permalink] New post   26 Jan 2004, 11:36
mba wrote:
assuming x is the weight of 2nd type and y of 1st type.

So we have total value as:
y*20+x*24+2*30 ----> 20y+24x+60

Now in the market it was sold at 20% profit at 30Rs/kg, which means

(20y+24x+60)+(20/100)*(20y+24x+60) = 30(x+y+2)

which on resolving will give
x+5y=10

Only option that satisfies the above scenario is 5.


You are again assuming that Y is integer. But that is unwarranted.
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Re: A merchant mixes three varieties of rice costing Rs.20/kg, [#permalink] New post   29 Jan 2004, 14:21
got the 5. Solution is same as mba
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Re: A merchant mixes three varieties of rice costing Rs.20/kg, [#permalink] New post   08 Jun 2015, 12:05
gmatblast wrote:
A merchant mixes three varieties of rice costing Rs.20/kg, Rs.24/kg and Rs.30/kg and sells the mixture at a profit of 20% at Rs.30 / kg. How many kgs of the second variety will be in the mixture if 2 kgs of the third variety is there in the mixture?

(1) 1 kg (2) 5 kgs (3) 3 kgs (4) 6 kgs



Could anybody provide a solution for the above problem?

Note: we cannot assume that quantity values will be integer only.
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Re: A merchant mixes three varieties of rice costing Rs.20/kg, [#permalink] New post   08 Jun 2015, 18:19
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Hi earnit,

This series of posts is over 11 years old, so you're not likely to hear from any of the posters.

As it stands, this question is incomplete and is not written in proper GMAT 'style', so you can ignore it. The biggest 'issue' is that you need to know how many kg's of the first type of rice you have (and that info was not provided). IF we were told that there was 1 kg of that first type of rice, then the correct answer would be 5kg of the second type of rice.

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Re: A merchant mixes three varieties of rice costing Rs.20/kg, [#permalink] New post   14 Aug 2018, 01:07
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Re: A merchant mixes three varieties of rice costing Rs.20/kg, [#permalink]
14 Aug 2018, 01:07
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