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# A merchant mixes three varieties of rice costing Rs.20/kg,

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Senior Manager
Joined: 11 Nov 2003
Posts: 349
Location: Illinois
A merchant mixes three varieties of rice costing Rs.20/kg,  [#permalink]

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17 Jan 2004, 16:57
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A merchant mixes three varieties of rice costing Rs.20/kg, Rs.24/kg and Rs.30/kg and sells the mixture at a profit of 20% at Rs.30 / kg. How many kgs of the second variety will be in the mixture if 2 kgs of the third variety is there in the mixture?

(1) 1 kg (2) 5 kgs (3) 3 kgs (4) 6 kgs
Manager
Joined: 26 Dec 2003
Posts: 220
Location: India

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17 Jan 2004, 17:02
Hey gmatblast how many kgs of the first variety does he mixes
Senior Manager
Joined: 11 Nov 2003
Posts: 349
Location: Illinois

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17 Jan 2004, 17:03
rakesh1239 wrote:
Hey gmatblast how many kgs of the first variety does he mixes

That is exactly my problem. It is not given. But there is an answer to this problem. and not sure whether that is correct or not.
Manager
Joined: 26 Dec 2003
Posts: 220
Location: India

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17 Jan 2004, 17:11
I got the answer has 5kg by assuming the first variety has 1 kg. here it is 1kg----- Rs 20/kg, x kg-------- Rs 24/kg and 2kg----- Rs 30/kg and sells it at 20% profit of y-y @ 30 = Rs 25/kg. so (1+x+2) kgs @ 25 = 20+ 24x + 60 solve for x and we get 5 kgs but I guess the question is wrong
Senior Manager
Joined: 26 Jan 2004
Posts: 388
Location: India

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26 Jan 2004, 10:27
assuming x is the weight of 2nd type and y of 1st type.

So we have total value as:
y*20+x*24+2*30 ----> 20y+24x+60

Now in the market it was sold at 20% profit at 30Rs/kg, which means

(20y+24x+60)+(20/100)*(20y+24x+60) = 30(x+y+2)

which on resolving will give
x+5y=10

Only option that satisfies the above scenario is 5.
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Senior Manager
Joined: 11 Nov 2003
Posts: 349
Location: Illinois

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26 Jan 2004, 10:36
mba wrote:
assuming x is the weight of 2nd type and y of 1st type.

So we have total value as:
y*20+x*24+2*30 ----> 20y+24x+60

Now in the market it was sold at 20% profit at 30Rs/kg, which means

(20y+24x+60)+(20/100)*(20y+24x+60) = 30(x+y+2)

which on resolving will give
x+5y=10

Only option that satisfies the above scenario is 5.

You are again assuming that Y is integer. But that is unwarranted.
SVP
Joined: 30 Oct 2003
Posts: 1740
Location: NewJersey USA

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29 Jan 2004, 13:21
got the 5. Solution is same as mba
Current Student
Joined: 06 Mar 2014
Posts: 243
Location: India
GMAT Date: 04-30-2015
Re: A merchant mixes three varieties of rice costing Rs.20/kg,  [#permalink]

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08 Jun 2015, 11:05
gmatblast wrote:
A merchant mixes three varieties of rice costing Rs.20/kg, Rs.24/kg and Rs.30/kg and sells the mixture at a profit of 20% at Rs.30 / kg. How many kgs of the second variety will be in the mixture if 2 kgs of the third variety is there in the mixture?

(1) 1 kg (2) 5 kgs (3) 3 kgs (4) 6 kgs

Could anybody provide a solution for the above problem?

Note: we cannot assume that quantity values will be integer only.
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Re: A merchant mixes three varieties of rice costing Rs.20/kg,  [#permalink]

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08 Jun 2015, 17:19
Hi earnit,

This series of posts is over 11 years old, so you're not likely to hear from any of the posters.

As it stands, this question is incomplete and is not written in proper GMAT 'style', so you can ignore it. The biggest 'issue' is that you need to know how many kg's of the first type of rice you have (and that info was not provided). IF we were told that there was 1 kg of that first type of rice, then the correct answer would be 5kg of the second type of rice.

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Re: A merchant mixes three varieties of rice costing Rs.20/kg,  [#permalink]

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14 Aug 2018, 00:07
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Re: A merchant mixes three varieties of rice costing Rs.20/kg, &nbs [#permalink] 14 Aug 2018, 00:07
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