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7^b + 7^b + 7^b + 7^b + 7^b + 7^b + 7^b =

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Bunuel
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7^b + 7^b + 7^b + 7^b + 7^b + 7^b + 7^b = [#permalink] New post   12 Dec 2015, 09:04
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\(7^b + 7^b + 7^b + 7^b + 7^b + 7^b + 7^b =\)


A. \(7^b\)

B. \(7^{(b + 1)}\)

C. \(7^{(7b)}\)

D. \(8^b\)

E. \(49^b\)
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chetan2u
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7^b + 7^b + 7^b + 7^b + 7^b + 7^b + 7^b = [#permalink] New post   26 Dec 2015, 04:28
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Htlol wrote:
I'm not able to make sense of this, can someone please explain the theory behind this?



Hi,
\(7^b + 7^b + 7^b + 7^b + 7^b + 7^b + 7^b = 7 * 7^b\)

now \(7 * 7 ^b =7^1*7^b=7^{(b+1)}\)as per the property of power..

B
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Re: 7^b + 7^b + 7^b + 7^b + 7^b + 7^b + 7^b = [#permalink] New post   12 Dec 2015, 09:18
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Easy one.

7*7^b = 7^(b+1)

Ans. B
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Re: 7^b + 7^b + 7^b + 7^b + 7^b + 7^b + 7^b = [#permalink] New post   26 Dec 2015, 04:20
I'm not able to make sense of this, can someone please explain the theory behind this?
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Re: 7^b + 7^b + 7^b + 7^b + 7^b + 7^b + 7^b = [#permalink] New post   26 Dec 2015, 05:00
chetan2u wrote:
Htlol wrote:
I'm not able to make sense of this, can someone please explain the theory behind this?



Hi,
\(7^b + 7^b + 7^b + 7^b + 7^b + 7^b + 7^b = 7 * 7^b\)

now \(7 * 7 ^b =7^1*7^b=7^(b+1)\)as per the property of power..


Now it makes much more sense. Kudos!
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Re: 7^b + 7^b + 7^b + 7^b + 7^b + 7^b + 7^b = [#permalink] New post   26 Oct 2017, 15:39
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Bunuel wrote:
7^b + 7^b + 7^b + 7^b + 7^b + 7^b + 7^b =

A. 7^b
B. 7^(b + 1)
C. 7^(7b)
D. 8^b
E. 49^B


Simplifying the equation, we have:

7^b + 7^b + 7^b + 7^b + 7^b + 7^b + 7^b

7^b(1 + 1 + 1 + 1 + 1 + 1 + 1)

7^b(7) = 7^(b + 1)

Answer: B
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Re: 7^b + 7^b + 7^b + 7^b + 7^b + 7^b + 7^b = [#permalink] New post   18 Oct 2018, 21:31
Given 7^b + 7^b + 7^b + 7^b + 7^b + 7^b + 7^b

Just added the above to give us = 7*7^b

and since bases are same, we can add the exponents

Giving answer as B => 7^(b+1)
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Re: 7^b + 7^b + 7^b + 7^b + 7^b + 7^b + 7^b = [#permalink] New post   31 May 2022, 07:48
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Re: 7^b + 7^b + 7^b + 7^b + 7^b + 7^b + 7^b = [#permalink]
31 May 2022, 07:48
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