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Re: Cathy has equal numbers of nickels and quarters worth a total of $7.50 [#permalink]
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Bunuel wrote:
Cathy has equal numbers of nickels and quarters worth a total of $7.50. How many coins does she have?
(nickel = 5 cents, quarter = 25 cents)

(A) 20
(B) 25
(C) 50
(D) 62
(E) 70

Number of nickels and quarters is equal, so

Let C = 1/2 of total number of coins

(Equal #s of coins times different values of coins, then summed, given a total of $7.50, will yield # of coins)

.05C + .25C = 7.50 ==>

5C + 25C = 750

30 C = 750, and

C = 25

TOTAL coins? C = 1/2 of total, so 2C = 50 coins total
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Re: Cathy has equal numbers of nickels and quarters worth a total of $7.50 [#permalink]
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Bunuel wrote:
Cathy has equal numbers of nickels and quarters worth a total of $7.50. How many coins does she have?
(nickel = 5 cents, quarter = 25 cents)

(A) 20
(B) 25
(C) 50
(D) 62
(E) 70


\(\frac{5}{100}*n + \frac{25}{100}n = 7.50\)

Or, \(30n = 750\)

Or, n = 25

So, Total number of coins with Cathy is 25*2 = 50 coins...

Thus, answer must be (C) 50
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Re: Cathy has equal numbers of nickels and quarters worth a total of $7.50 [#permalink]
5x + 25 X = 750
30 x = 750
x= 25,,

total number of coins = 25 + 25 = 50.. ans C
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Re: Cathy has equal numbers of nickels and quarters worth a total of $7.50 [#permalink]
Expert Reply
Bunuel wrote:
Cathy has equal numbers of nickels and quarters worth a total of $7.50. How many coins does she have?
(nickel = 5 cents, quarter = 25 cents)

(A) 20
(B) 25
(C) 50
(D) 62
(E) 70

Source: Nova GMAT
Difficulty Level: 700


We can create the equation:

0.05n + 0.25n = 7.5

5n + 25n = 750

30n = 750

n = 25

So, she has a total of 25 + 25 = 50 coins.

Answer: C
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Re: Cathy has equal numbers of nickels and quarters worth a total of $7.50 [#permalink]
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Re: Cathy has equal numbers of nickels and quarters worth a total of $7.50 [#permalink]
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