Bunuel wrote:
The circle in the figure above has center O. Which of the following measures for the figure would be sufficient by itself to determine the radius of the circle?
I. The length of arc PQR
II. The perimeter of ∆ OPR
III. The length of the chord PR
(A) None
(B) I only
(C) II only
(D) III only
(E) I, II and III
Attachment:
2017-11-21_1003_001.png
Assess options: Enough to determine radius?
My analysis does not involve trig.
There is an isosceles right triangle created by two radii and a 90° angle.
\(\frac{SectorArea}{CircleArea}=\frac{SectorAngle}{360°}=\frac{90°}{360°}=\frac{1}{4}\)Sector OPR = \(\frac{1}{4}\) of circle
I. The length of arc PQR? YES
Arc PQR is \(\frac{1}{4}\) of the circumference, so
Length of arc PQR * 4 = circumference = 2πr
From circumference, find radius
If PQR had arc length \(2π\), e.g.:
(Arc length) * 4 = Circumference
\(2π * 4 = 2πr\)
\(8π = 2πr\)
\(8 = 2r\)
\(r=4\)
II. The perimeter of ∆ OPR? YES
∆ OPR is right isosceles, with
--legs that are radii and
--side lengths in ratio
\(r : r : r\sqrt{2}\)Perimeter of ∆ OPR =
\((r + r + r\sqrt{2})= (2r + r\sqrt{2})\)If perimeter were
\(8 + 4\sqrt{2}\):
\(8 = 2r\), and
\(r = 4\)(Third side ratio holds: PR =
\(4\sqrt{2}\))
I would stop here. The only choice that has both I and II is answer E.
III. The length of the chord PR? YES
Chord PR, per side length ratio of 45-45-90 (right isosceles) triangles, means
Length of chord PR =
\(r\sqrt{2}\) If PR length were, e.g., 8:
\(8 = r\sqrt{2}\)
\(\frac{8}{\sqrt{2}} = r\)
\(r =(\frac{8}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}})=4\sqrt{2}=r\)All three are sufficient to find radius.
Answer E