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Re: T1 and T2 are two sets containing integers only. If an integer X is [#permalink]
EgmatQuantExpert wrote:

Solution:



\(X\)-> a number from the set T1.
\(Y\)-> a number from the set T2.

\(Y^X\) is even only when \(Y\) is even and \(X\) is positive.

Thus, we need to find the probability of selecting even values of \(Y\).

Statement-1 is “T1 = {-16, -4, 0, 6, 12}”.

Since only \(X\) is selected from \(T1\), we cannot find the possible values of \(Y\) from this statement.

Thus, Statement 1 alone is not sufficient to answer the question.

Statement-2 is “T2 = {-17, -15, -11, 19, 25}”.

Since \(T2\) does not have any even number. Hence, there are no possible values of \(Y\).

Thus, the probability that \(Y^X\) is even is \(0\).

Statement 2 alone is sufficient to answer the question.

Answer: B



If we take the element 25 from T2, raise it to power -2 (question only says integer), then it results in an even number. With that, can we still say B is sufficient?
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Re: T1 and T2 are two sets containing integers only. If an integer X is [#permalink]
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Re: T1 and T2 are two sets containing integers only. If an integer X is [#permalink]
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