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# T1 and T2 are two sets containing integers only. If an integer X is

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DS Forum Moderator
Joined: 21 Aug 2013
Posts: 1432
Location: India
T1 and T2 are two sets containing integers only. If an integer X is  [#permalink]

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15 Mar 2018, 22:37
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45% (medium)

Question Stats:

54% (01:18) correct 46% (01:17) wrong based on 58 sessions

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T1 and T2 are two sets containing integers only. If an integer X is randomly selected from T1 and another integer Y is randomly selected from T2, what is the probability that Y^X (Y raised to the power X) is even?

(1) T1 = {-16, -4, 0, 6, 12}

(2) T2 = {-17, -15, -11, 19, 25}
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Joined: 18 Dec 2017
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GMAT 1: 650 Q45 V35
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Re: T1 and T2 are two sets containing integers only. If an integer X is  [#permalink]

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17 Mar 2018, 12:59
Odd^Odd is always Odd. and Odd^Even is also always odd. So We just need to know if Y in Y^X is even or ODD. Since all the numbers in Y are odd. The answer will be NO.
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T1 and T2 are two sets containing integers only. If an integer X is  [#permalink]

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21 Mar 2018, 00:04

Solution:

$$X$$-> a number from the set T1.
$$Y$$-> a number from the set T2.

$$Y^X$$ is even only when $$Y$$ is even and $$X$$ is positive.

Thus, we need to find the probability of selecting even values of $$Y$$.

Statement-1 is “T1 = {-16, -4, 0, 6, 12}”.

Since only $$X$$ is selected from $$T1$$, we cannot find the possible values of $$Y$$ from this statement.

Thus, Statement 1 alone is not sufficient to answer the question.

Statement-2 is “T2 = {-17, -15, -11, 19, 25}”.

Since $$T2$$ does not have any even number. Hence, there are no possible values of $$Y$$.

Thus, the probability that $$Y^X$$ is even is $$0$$.

Statement 2 alone is sufficient to answer the question.

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T1 and T2 are two sets containing integers only. If an integer X is &nbs [#permalink] 21 Mar 2018, 00:04
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