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Math Revolution GMAT Instructor
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Re: What is the perimeter of a rectangle? [#permalink]
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MathRevolution wrote:
[Math Revolution GMAT math practice question]

What is the perimeter of a rectangle?

1) The square of the diagonal is \(52\).
2) The area of the rectangle is \(24\).


\(? = {\text{perim}}\left( {{\text{rectangle}}} \right)\)

Excellent opportunity to GEOMETRICALLY BIFURCATE each statement alone:

\(\left( 1 \right)\,\,\,{\text{dia}}{{\text{g}}^{\,{\text{2}}}} = 52\,\,\,\,\,\,\mathop \Rightarrow \limits^{{\text{diag}}\,\, > \,\,0} \,\,\,{\text{diag}}\,\,{\text{unique}}\,\,\,{\text{but}}\,\,\,{\text{INSUFF}}.\)

\(\left( 2 \right)\,\,\,{\text{area}} = 24\,\,\,\,\, \Rightarrow \,\,\,\,{\text{INSUFF}}{\text{.}}\)

(See the image attached!)

\(\left( {1 + 2} \right)\)

Let L and W be the length and width of our focused-rectangle. Hence:

\(? = {\text{2}}\left( {L + W} \right)\)

\(\left( {1 + 2} \right)\,\,\left\{ \begin{gathered}\\
{L^2} + {W^2} = 52 \hfill \\\\
2LW = 2 \cdot 24\,\,\,\, \hfill \\ \\
\end{gathered} \right.\,\,\,\,\mathop \Rightarrow \limits^{\left( + \right)} \,\,\,\,\,{\left( {L + W} \right)^2} = 52 + 48 = 100\)

\({\left( {L + W} \right)^2} = 100\,\,\,\,\mathop \Rightarrow \limits^{L + W\,\, > \,\,0} \,\,\,\,L + W\,\,\,{\text{unique}}\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,? = 2\left( {L + W} \right)\,\,\,\,{\text{unique}}\)


This solution follows the notations and rationale taught in the GMATH method.

Regards,
fskilnik.
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Math Revolution GMAT Instructor
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Re: What is the perimeter of a rectangle? [#permalink]
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=>

Forget conventional ways of solving math qAnswer: CAnswer: Cuestions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

When we apply VA method to geometry, we need to count the number of variables. For a rectangle, we have two variables for the length and the width of the rectangle. Let x and y be the length of the width of the rectangle, respectively.

Since we have 2 variables (x and y) and 0 equations, C is most likely to be the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)
We have \(x^2+y^2 = 52\) by Pythagoras’ theorem, and \(Area = xy = 24.\)
So, \((x+y)^2 = x^2+2xy + y^2 = (x^2+y^2) +2xy = 52 + 48 = 100.\)
Therefore, \(x+y = 10\) and we can calculate the perimeter.
Both conditions (together) are sufficient.

Therefore, C is the answer.
Answer: C
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