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Intern
Joined: 13 Jan 2018
Posts: 30
Location: India
Concentration: Operations, Strategy
GMAT 1: 530 Q46 V17 
GMAT 2: 640 Q49 V28
Tom will cultivate bacteria. The number of bacteria he will cultivate
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26 May 2019, 23:43
26 May 2019, 23:43
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Tom will cultivate bacteria. The number of bacteria he will cultivate after one day is 150 percent of that of the previous day. The total number of bacteria is 4,725 after 2 days. What is the value of the original number of bacteria on the first day?
A. 1,200 B. 1,500 C. 1,600 D. 1,800 E. 2,100
A. 1,200 B. 1,500 C. 1,600 D. 1,800 E. 2,100
Re: Tom will cultivate bacteria. The number of bacteria he will cultivate
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27 May 2019, 01:46
27 May 2019, 01:46
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srij13 wrote:
Tom will cultivate bacteria. The number of bacteria he will cultivate after one day is 150 percent of that of the previous day. The total number of bacteria is 4,725 after 2 days. What is the value of the original number of bacteria on the first day?
A. 1,200 B. 1,500 C. 1,600 D. 1,800 E. 2,100
A. 1,200 B. 1,500 C. 1,600 D. 1,800 E. 2,100
Each day he will cultivate 150% of the number of the previous day.
So say he has x bacteria on 24th May, 12 midnight.
He will have (150/100)x bacteria on 25th May, 12 midnight.
And (150/100*(150/100)x bacteria on 26th may, 12 midnight.
So after two days, he has (150/100)*(150/100)x = 4725 bacteria
x = 2100
So original number of bacteria (beginning of the day) on the first day = 2100
Answer (E)
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General Discussion
Intern
Joined: 13 Jan 2018
Posts: 30
Location: India
Concentration: Operations, Strategy
GMAT 1: 530 Q46 V17
GMAT 2: 640 Q49 V28
Re: Tom will cultivate bacteria. The number of bacteria he will cultivate
[#permalink]
26 May 2019, 23:48
26 May 2019, 23:48
Can someone tell me how the equation comes out for the above question? What I did -
x= No of bacteria on day one
1.5x= No of bacteria on day two
Adding them together x + 1.5x = 4725
But this seems wrong.
Please Help!!! Bunuel
x= No of bacteria on day one
1.5x= No of bacteria on day two
Adding them together x + 1.5x = 4725
But this seems wrong.
Please Help!!! Bunuel
Re: Tom will cultivate bacteria. The number of bacteria he will cultivate
[#permalink]
26 May 2019, 23:53
26 May 2019, 23:53
srij13 wrote:
Can someone tell me how the equation comes out for the above question? What I did -
x= No of bacteria on day one
1.5x= No of bacteria on day two
Adding them together x + 1.5x = 4725
But this seems wrong.
Please Help!!! Bunuel
x= No of bacteria on day one
1.5x= No of bacteria on day two
Adding them together x + 1.5x = 4725
But this seems wrong.
Please Help!!! Bunuel
I'm getting 1350.
VP
Joined: 20 Jul 2017
Posts: 1299
Location: India
Concentration: Entrepreneurship, Marketing
GMAT 1: 690 Q51 V30
WE:Education (Education)
Tom will cultivate bacteria. The number of bacteria he will cultivate
[#permalink]
Updated on: 27 May 2019, 00:14
Updated on: 27 May 2019, 00:14
2
Kudos
srij13 wrote:
Tom will cultivate bacteria. The number of bacteria he will cultivate after one day is 150 percent of that of the previous day. The total number of bacteria is 4,725 after 2 days. What is the value of the original number of bacteria on the first day?
A. 1,200 B. 1,500 C. 1,600 D. 1,800 E. 2,100
A. 1,200 B. 1,500 C. 1,600 D. 1,800 E. 2,100
Initially = x
Total After day 1= x + 1.5x = 2.5x
Total After day 2= 1.5(2.5x) = 3.375x
So 3.375x = 4725
—> x = 1400
After first day = 1.5x = 2100
IMO E
Posted from my mobile device
Originally posted by CareerGeek on 27 May 2019, 00:06.
Last edited by CareerGeek on 27 May 2019, 00:14, edited 2 times in total.
Last edited by CareerGeek on 27 May 2019, 00:14, edited 2 times in total.
Re: Tom will cultivate bacteria. The number of bacteria he will cultivate
[#permalink]
27 May 2019, 00:09
27 May 2019, 00:09
Dillesh4096 wrote:
srij13 wrote:
Tom will cultivate bacteria. The number of bacteria he will cultivate after one day is 150 percent of that of the previous day. The total number of bacteria is 4,725 after 2 days. What is the value of the original number of bacteria on the first day?
A. 1,200 B. 1,500 C. 1,600 D. 1,800 E. 2,100
A. 1,200 B. 1,500 C. 1,600 D. 1,800 E. 2,100
Initially = x
On day 1 = 1.5x
After day 1= x + 1.5x = 2.5x
After day 2= 1.5(2.5x) = 3.375x
So 3.375x = 4725
—> x = 1400
On first day = 1.5x = 2100
IMO E
Posted from my mobile device
Aren't you counting 3 days?
VeritasKarishma please help.
Re: Tom will cultivate bacteria. The number of bacteria he will cultivate
[#permalink]
01 Jul 2019, 03:48
01 Jul 2019, 03:48
srij13 wrote:
Tom will cultivate bacteria. The number of bacteria he will cultivate after one day is 150 percent of that of the previous day. The total number of bacteria is 4,725 after 2 days. What is the value of the original number of bacteria on the first day?
A. 1,200 B. 1,500 C. 1,600 D. 1,800 E. 2,100
A. 1,200 B. 1,500 C. 1,600 D. 1,800 E. 2,100
If the right answer is E and the value of the original number of bacteria on the first day is 2100, that means that a number of bacterias on the 2nd day is 2100*1,5+2100=5250, but not 4725.
Can somebody explain this?
The way I see it:
x - bacterias on day 0
x+1,5x - bacterias on day 1
(x+1,5x)*1,5 = 4725 - bacterias on day 2
so let's find x
1,5x+2,25x=4725
3,75x=4725
x=1260 - this is on day 0, but we need on day 1, so
1260+1,5*1260=3150
Where am I wrong?
Thank you for help
Re: Tom will cultivate bacteria. The number of bacteria he will cultivate
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03 Apr 2023, 17:04
03 Apr 2023, 17:04
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Re: Tom will cultivate bacteria. The number of bacteria he will cultivate [#permalink]
03 Apr 2023, 17:04
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